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Lerok [7]
2 years ago
11

29. The chemical equation H2 + O2 + H2O represents what type of equation?

Chemistry
1 answer:
slavikrds [6]2 years ago
4 0

Answer:

The chemical equation H2 + O2 + H2O represents what type of equation?

A. A balanced equation

xXxAnimexXX

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How many days does it take 16.Og of Gold-198 to decay to 1.0g? (each half-
forsale [732]

Answer:

10.8 days (3 sig.figs.)

Explanation:

All radioactive decay is 1st order decay defined by the expression A = A₀e^-kt

which is solved for time of decay (t) => t = ln(A/A₀) / -k

A = final weight = 1.0 gram

A₀ = initial weight = 16.0 grams

k = rate constant = 0.693/t(1/2) = 0.693/2.69 days = 0.258 days⁻¹

t = ln(1/16) / -0.258da⁻¹ = (-2.77/-0.258) days = 10.74646792 days (calculator)

≅ 10 days (1 sig. fig. based on given 1 gram mass)

4 0
3 years ago
Sydney and Valparaiso are the same distance from the equator and both are near the ocean. Is Valparaiso warmer, colder, or the s
PilotLPTM [1.2K]

Answer: It's colder.

Explanation: Well for starters Valparaiso is further away from the equator, and Australia is already really hot. But say that Valparaiso is further from the equator should be good enough.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!!!
Akimi4 [234]

Answser

i didnt do dis my mom has a answer key book

Explanation:

4 0
3 years ago
How many grams of KBr is required to prepare 100 mL of<br> 2.0 M KBr solution?
sesenic [268]

Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)

= 0.2 mol

We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

We can now calculate the grams by using grams=mol x molar mass

119.023g/mol x 0.2mol

= 23.8046 g

=23.8g (rounded to 1decimal place)

4 0
3 years ago
Which of the following units is used to measure force ?
Sati [7]
C.) Newton. & it's S.I. Unit of Force.

Hope this helps!
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3 years ago
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