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horrorfan [7]
3 years ago
5

Which statement BEST describes what happens when a cold front approaches a warm front?

Chemistry
2 answers:
stepladder [879]3 years ago
7 0

Answer:

A

Explanation:

In a cold front set-up, the boundary between the cold and warm air masses is relatively steep, typically causing the warm air in front of it to rise rapidly.

katen-ka-za [31]3 years ago
5 0

Answer:

A

Explanation:

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Determine the specific heat of a 213.0 g piece of metal in J/g•°C if the temperature of the metal drops from 70.2 °C to 25.6 °C
ladessa [460]

Answer:

0.3415 J/g °C

Explanation:

M1 = 213.0g

c1 = ?

T1 = 70.2°C

T3 = 25.6 °C

T2 = 22.5°C

C2 = 4.186 J/g°C

Vol. of water = 250mL = 250cm³

p (density of water ) = 1g/L

p = mass / volume

mass (m) = density (p) * volume (v)

m = 1 * 250 = 250g

Heat loss by metal = heat gain by water

Q1 = Q2

Mc∇T = Mc∇T

Mc (T1 - T3) = Mc* (T3 - T2)

213 * c * (70.2 - 25.6) = 250 * 4.186 * (25.6 - 22.5)

(213 * 44.6)c = 1046.5 * 3.1

9499c = 3244.15

c = 0.3415 J/g.°C

The specific heat capacity of the metal is 0.3415 J/g °C

3 0
4 years ago
What is the kinetic energy of a 328 kg object that is moving at s speed of 10 m/s
Advocard [28]

16400 Joules is the kinetic energy of a 328kg object with a velocity of 10m/s.

<h3>What is the kinetic energy of the object?</h3>

Kinetic energy is simply energy possessed by a body in motion.

Kinetic energy is expressed as;

Kinetic energy = 1/2 × m × v²

Where v is velocity and m is mass of the object,

Given the data in the question;

  • Mass of the object m = 328kg
  • Velocity of the object = 10m/s
  • Kinetic energy = ?

To determine the kinetic energy of the object, plug the given values into the formula above.

Kinetic energy = 1/2 × m × v²

Kinetic energy = 1/2 × 328kg × (10m/s)²

Kinetic energy = 1/2 × 328kg × 100m²/s²

Kinetic energy = 328kg × 50m²/s²

Kinetic energy = 16400kgm²/s²

Kinetic energy = 16400J

Therefore, the kinetic energy 16400 Joules.

Learn more about kinetic energy here: brainly.com/question/27397088

#SPJ1

6 0
1 year ago
A buffer solution contains 0.11 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L. What is the pH of this buffer?
aleksley [76]

Answer:

Henderson Hasselbalch equation: pH = pKa + log [salt]/[acid]

You need to know the pKa for acetic acid. Looking it up one finds it to be 4.76

(a). pH = 4.76 + log [0.13]/[0.10]

= 4.76 + 0.11

= 4.87

(b) KOH + CH3COOH =>H2O + CH3COOK so (acid)goes down and (salt)goes up. Assuming no change in volume, you have 0.10 mol acid - 0.02 mol = 0.08 mol acid and 0.13 mol salt + 0.02 mol = 0.15 mol salt

pH = 4.76 + log [0.15]/[0.08]

= 4.76 + 0.27

= 5.03

5 0
4 years ago
What is an ionic bond?
ollegr [7]
<span>D. a bond in which electrons are transferred 

</span>Ionic bonding<span> is the complete transfer of valence electron(s) between atoms</span>
6 0
4 years ago
Read 2 more answers
How does convection occur in the troposhere ​
adell [148]

Answer:The surface heated air expands as it warms, becomes less dense than surrounding cooler air and rises as buoyant and turbulent bubbles. This is convection and is the main process by which the troposphere mixes and heats. Although convection stirs and mixes the troposphere, the higher it is the colder it becomes.

Explanation: Read this and you'll get your answer~! I hope i helped you~! Have an GREAT day too~! <\3

7 0
4 years ago
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