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vlada-n [284]
3 years ago
10

Help me please Which line shows the LOWEST frequency?

Physics
1 answer:
fomenos3 years ago
8 0
I want to say it's the second one because the crest's of the wave are further apart then the rest.
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Convert 120 Kelvin to Fahrenheit​
natita [175]

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-243.67°F

Explanation:

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Can you answer this math homework? Please!
aleksklad [387]

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I've combined both answers on a single graph.

Explanation:

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What should not be used to support a scaffold because they could collapse, sending the structure to the ground?
uranmaximum [27]

Answer:

Cinder blocks

Explanation:

From safety training guides, whenever there is inadequate support, poor

construction, or a movement in the components of the scaffold such as the coupler as well as the base upon which the scaffold structure is built, there will be a great danger of collapse.

In light of this safety rule, Cinder blocks such as sandcrete blocks, bricks e.t.c shouldn't be used to support scaffold because they have a high tendency of being crushed under load

5 0
3 years ago
Please help. All the information is in the image.
kondaur [170]

The tiger's position at time <em>t</em> is given by

<em>x</em> (horizontal) = (4.5 m/s) <em>t</em>

<em>y</em> (vertical) = 7.5 m - 1/2 <em>gt</em> ²

Solve <em>y</em> = 0 for <em>t</em> to find the time it takes for the tiger to reach the ground :

0 = 7.5 m - 1/2 (9.8 m/s²) <em>t</em> ²

===>   <em>t</em> = √(2 (7.5 m) / (9.8 m/s²)) ≈ 1.2 s

Evaluate <em>x</em> at this time :

<em>x</em> = (4.5 m/s) (1.2 s) ≈ 5.6 m

5 0
3 years ago
A brick is thrown upward from the top of a building at an angle of 10° to the horizontal and with an initial speed of 16 m/s. If
Basile [38]

Answer:

38.47 m

Explanation:

To find the height of the building, we will use the following equation

y_f=y_i+v_{iy}t+\frac{1}{2}at^2

Where yf is the final height, yi is the initial height, viy is the initial vertical velocity, t is the time, and a is the acceleration due to gravity.

If the brick is in flight for 3.1 s, we can say that when t = 3.1s, yf = 0 m. So, replacing

viy = (16 m/s)sin(10) = 2.78 m/s

a = -9.8 m/s²

we get

0=y_i+2.78(3.1)+\frac{1}{2}(-9.8)(3.1)^2

Solving for yi

\begin{gathered} 0=y_i-38.48 \\ y_i=38.48\text{ m} \end{gathered}

Therefore, the height of the building is 38.48 m

6 0
1 year ago
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