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Anna11 [10]
3 years ago
5

Which experimental evidence indicates that. electron are negatively charged particles​

Physics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer:

Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

Vinil7 [7]3 years ago
8 0

Answer:

thomsons experiment he used ray tubes that showed all electrons contain negatively cahrged particles

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two point charges of 3.4 μc and 6.6 μc are 0.20 m apart. what is the electrical potential energy of the system?
Daniel [21]

Explanation:

electrical potential = (6.6-3.4)/0.20

= 16 uc/m

8 0
2 years ago
An object with a mass of 2.0 kg is accelerated at 5.0 m/s/s. the net force acting on the mass is
Vitek1552 [10]
First we need to know the equation:
F= Mass times acceleration
F = 2.0 kg times 5.0 m/s^2 
multiply them to get the net force!
F= 10 N 
N is newton 
Hope this heps
7 0
3 years ago
Read 2 more answers
How to use kinetic energy to calculate velocity
BartSMP [9]

As we know the formula of kinetic energy is

KE = \frac{1}{2} mv^2

here given that

KE = 150,000 J

mass = 120 kg

we can use this to find speed

150,000 = \frac{1}{2} * 120 * v^2

v^2 = 2500

v = 50 m/s

So speed of above object is 50 m/s

7 0
3 years ago
A point charge is placed 100 m from a 6 uC charge generating an electric field. What is the
kvv77 [185]

The strength of the electric field is 5 N/C

Explanation:

The magnitude of the electric field produced by a single-point charge is given by:

E=\frac{kQ}{r^2}

where

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

Q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

Q=6 \mu C = 6\cdot 10^{-6}C is the charge producing the field

r = 100 m is the distance from the charge at  which we want to calculate the field

Substituting into the equation, we find the s trength of the electric field:

E=\frac{(8.99\cdot 10^9)(6\cdot 10^{-6})}{(100)^2}=5.4 N/C \sim 5 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
The resistance created by waves on a 120-m-long ship is tested in a channel using a model that is 4 m long Y Part A If the ship
DanielleElmas [232]

Answer:

V_m = 12.78 km/hr

Explanation:

given,

length of the ship = 120 m

length of model of the ship = 4 m

Speed at which the ship travels = 70 km/h

speed of model = ?

by using froude's law

  F_r = \dfrac{V}{\sqrt{L g}}

for dynamic similarities

  (\dfrac{V}{\sqrt{L g}})_P = (\dfrac{V}{\sqrt{L g}})_{model}

  (\dfrac{V_p}{\sqrt{L_p}}) = (\dfrac{V_m}{\sqrt{L_m}})

  (\dfrac{70}{\sqrt{120}}) = (\dfrac{V_m}{\sqrt{4}})

          V_m = 12.78 km/hr

hence, the velocity of model will be 12.78 km/h

6 0
3 years ago
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