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Anna11 [10]
2 years ago
5

Which experimental evidence indicates that. electron are negatively charged particles​

Physics
2 answers:
Anastaziya [24]2 years ago
8 0

Answer:

Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

Vinil7 [7]2 years ago
8 0

Answer:

thomsons experiment he used ray tubes that showed all electrons contain negatively cahrged particles

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There are three fundamental forces that act at a distance. They are gravitational, electromagnetic and nuclear forces.
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20 POINTS! TRUE OR FALSE:
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False.

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Kinetic energy means it must move

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Estimate the number of time your heart beats in an average day
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Your heart beats approximately once per second. There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, 365.25 days in a year, and approximately 75 years in a lifetime.
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3 years ago
Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu
KiRa [710]

Answer:

(a) Determine the astronaut's orbital speed

The velocity of the astronaut is 1436m/s.

(b) Determine the period of the orbit.  

The period of the orbit is 10413 seconds.

Explanation:

<em>(a) Determine the astronaut's orbital speed</em>

The orbital speed of astronaut can be found by means of the Universal law of gravity:        

F = G\frac{M \cdot m}{r^{2}}   (1)

Then, replacing Newton's second law in equation 3 it is gotten:

m\cdot a  = G\frac{M \cdot m}{r^{2}}  (2)

However, a is the centripetal acceleration since the astronaut describes a circular motion around the Moon:

a = \frac{v^{2}}{r}  (3)

Replacing equation 3 in equation 2 it is gotten:

m\frac{v^{2}}{r} = G\frac{M \cdot m}{r^{2}}

m \cdot v^{2} = G \frac{M \cdot m}{r^{2}}r

m \cdot v^{2} = G \frac{M \cdot m}{r}

v^{2} = G \frac{M \cdot m}{rm}

v^{2} = G \frac{M}{r}

v = \sqrt{\frac{G M}{r}} (4)

   

Where v is the orbital speed, G is the gravitational constant, M is the mass of the Moon, and r is the orbital radius.        

Notice that the orbital radius will be given by the sum of the radius of the Moon and the height of the astronaut above the surface.

       

But it is necessary to express the height of the astronaut above the surface in units of meters before it can be used.

r = 680km \cdot \frac{1000m}{1km} ⇒ 680000m

r = 1.70x10^{6}m+680000m

       

r = 2380000m

However it is neccesary to find the mass of Moon in order to use equation 4.

Then Newton's second law (F = ma) will be replaced in equation (1):

ma = G\frac{Mm}{r^{2}}

Then, M will be isolated

M = \frac{r^{2}a}{G} (5)

Where r is the orbital radius of the astronaut and a is the acceleration due to gravity.

M = \frac{(2380000m)^{2}(0.867 m/s^{2})}{6.67x10^{-11}N.m^{2}/kg^{2}} (5)

M = 7.36x10^{22}Kg

v = \sqrt{\frac{(6.67x10^{-11}N.m^{2}/kg^{2})(7.36x10^{22}Kg)}{2380000m}}

                         

v = 1436m/s

                                 

Hence, the velocity of the astronaut is 1436m/s.  

                                 

<em>(b) Determine the period of the orbit.       </em>  

The period of the orbit can be determined by the next equation:

v = \frac{2\pi r}{T}  (6)

Where v is the orbital velocity, r is the orbital radius and T is the period of the orbit.

                       

Then, T can be isolated from equation 6.

T = \frac{2\pi r}{v} (7)

T = \frac{2\pi (2380000m)}{1436m/s}

         

T = 10413s         

Hence, the period of the orbit is 10413 seconds.                                      

6 0
3 years ago
Which of the following is NOT a characteristic of scientific knowledge?
sertanlavr [38]
Hello.

The answer is 

<span>Scientific knowledge can answer all of society's questions.
</span>
All Science has limits, some things sciencets cant do things becuase its not possible  or its just not for science. 

It cant be the first one becasue everyone chnages there mind.

It cant be two becasue sciencet only do experments that are safe so they wil be durable.

So its C

Have a nice day
8 0
3 years ago
Read 2 more answers
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