Answer:
is reflected back into the region of higher index
Explanation:
Total internal reflection is a phenomenon that occurs when all the light passing from a region of higher index of refraction to a region of lower index is reflected back into the region of higher index.
According to Snell's law, refraction of ligth is described by the equation
where
n1 is the refractive index of the first medium
n2 is the refractive index of the second medium
is the angle of incidence (in the first medium)
is the angle of refraction (in the second medium)
Let's now consider a situation in which
so light is moving from a medium with higher index to a medium with lower index. We can re-write the equation as
Where 
is a number greater than 1. This means that above a certain value of the angle of incidence , the term on the right can become greater than 1. So this would mean
But this is not possible (the sine cannot be larger than 1), so no refraction occurs in this case, and all the light is reflected back into the initial medium (total internal reflection). The value of the angle of incidence above which this phenomen occurs is called critical angle, and it is given by
Answer:
The frictional force 
6.446 N
The acceleration of the block a = 6.04 
Explanation:
Mass of the block = 3.9 kg
°
= 0.22
(a). The frictional force is given by
3.9 × 9.81 × 
29.3 N
Therefore the frictional force
0.22 × 29.3
6.446 N
(b). Block acceleration is given by
F = 30 N
= 6.446 N
= 30 - 6.446
= 23.554 N
The net force acting on the block is given by
23.554 = 3.9 × a
a = 6.04
This is the acceleration of the block.
Charge on electron is 1.6x10^-19 Coulombs.In uniform circular motion v = r omega. omega = v/r. omega= 61/3.8 radians per second - cycle is 2pi radians. (61/3.8)x2pi cycles per second. A charge circulation rate of (61/3.8)x2pix1.6x10^-19 Coulombs/second, or Amps. Which is a pretty small value of a current. Usually there many more electrons moving much faster, I think.
Answer:
Vf = 21.5 [m/s]
Explanation:
To solve this problem we must use the following kinematics equation:
where:
Vf = final velocity [m/s]
Vi = initial velocity = 0
a = aceleration = 4.3 [m/s^2]
t = time = 5 [s]
Now replacing:
Vf = 0 + (4.3*5)
Vf = 21.5 [m/s]
