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dimulka [17.4K]
3 years ago
15

Ang larong Latin at Sisiw ay________________________.

Physics
1 answer:
brilliants [131]3 years ago
3 0

larong pinoy

Explanation:

ito ay larong Pinoy

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Astronomers have recently observed stars orbiting at very high speeds around an unknown object near the center of our galaxy. Fo
nataly862011 [7]

Answer:

<em>The mass of the object is 745000 units of the sun</em>

Explanation:

We know that the centripetal force with which the stars orbit the object is represented as

F_{c} = \frac{mv^{2} }{r}

and this centripetal force is also proportional to

F_{c} = \frac{kMm}{r^{2} }

where

m is the mass of the stars

M is the mass of the object

v is the velocity of the stars = 10^6 m/s

r is the distance between the stars and the object = 10^14 m

k is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2

We can equate the two centripetal force equations to give

\frac{mv^{2} }{r} = \frac{kMm}{r^{2} }

which reduces to

v^{2} = \frac{kM}{r}

and then finally

M = \frac{rv^{2} }{k}

substituting values, we have

M = \frac{10^{14}*(10^{6})^{2}  }{6.67*10^{-11} } = 1.49 x 10^36 kg

If the mass of the sun is 2 x 10^30 kg

then, the mass of the the object in units of the mass of the sun is

==> (1.49 x 10^36)/(2 x 10^30) = <em>745000 units of sun</em>

6 0
3 years ago
What do all heterotrophs have in common?
ss7ja [257]

Answer:

c

Explanation:

your welcome dude good luck

6 0
3 years ago
Develop expression for equation for uniform motion in a straight line
frozen [14]
According to cuneiform tablets in the ancient world, straight lines cannot cross, and no motion in the world is not relative. Btw...I KNOW!!! GOT MILK???
4 0
3 years ago
What is the current if 4C of charge passes in 2 s?
julia-pushkina [17]

Answer:

I hope 2 amperes of current passes

8 0
3 years ago
A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around
jolli1 [7]

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground=\mu_s=0.8

\mu_k=0.5

Static friction force,f=\mu N

Normal force=N=mg

Static friction force,f=\mu_s mg=0.8\times 100\times 9.8=784 N

Using g=9.8m/s^2

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.

4 0
3 years ago
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