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german
3 years ago
6

The actual yield of a product in a reaction was measured as 4.20 g. If the theoretical yield of the product for the reaction is

4.88 g, what is the percentage yield of the product? (4 points) Question 17 options: 1) 82.6% 2) 84.2% 3) 86.1% 4) 88.0%
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

3

Explanation:

remember the equation percentage yield = actual/ theoretical yield as

4.20/4.88 x 100

86.065 so 86.1.

hope this make sense:)

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Answer:

\large \boxed{109.17 \, ^{\circ}\text{C}}

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4. Increase in boiling point

\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}

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\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}

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