Answer:
20 Joules
Explanation:
Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.
Therefore, we have;
Work done = Force x distance
i.e Wd = Fs
Given that: F = 20 N and s = 1 m, then;
Wd = 20 N x 1 m
= 20 Nm
The work done by the father is 20 Joules(Nm).
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➷ It would be C
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To solve this problem it is necessary to apply the concepts related to energy in photons. Although these although they have no mass have energy and are defined as
![E = hf= \frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%20%3D%20hf%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
Where,
c = Speed of light
h = Planck's constant![\rightarrow 6.626*10^{-34}](https://tex.z-dn.net/?f=%5Crightarrow%206.626%2A10%5E%7B-34%7D)
= wavelength
f= Frequency of the radiation
In addition to this we know that the maximum kinetic energy in a photon is given by the formula
![k_{max} = hf-\phi](https://tex.z-dn.net/?f=k_%7Bmax%7D%20%3D%20hf-%5Cphi)
Where,
Amount of energy binding the electron to the metal
can be expressed also as
![\phi = \frac{hc}{\lambda}-k](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D-k)
Replacing the terms then we have to
![E = K+\phi](https://tex.z-dn.net/?f=E%20%3D%20K%2B%5Cphi)
![\frac{hc}{\lambda_2} = k_2 +(\frac{hc}{\lambda_1}-k_1)](https://tex.z-dn.net/?f=%5Cfrac%7Bhc%7D%7B%5Clambda_2%7D%20%3D%20k_2%20%2B%28%5Cfrac%7Bhc%7D%7B%5Clambda_1%7D-k_1%29)
Re-arrange to find ![k_2,](https://tex.z-dn.net/?f=k_2%2C)
![k_2 = \frac{hc}{\lambda_2} -(\frac{hc}{\lambda_1}-k_1)](https://tex.z-dn.net/?f=k_2%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda_2%7D%20-%28%5Cfrac%7Bhc%7D%7B%5Clambda_1%7D-k_1%29)
![k_2 = \frac{hc}{\lambda_2} -\frac{hc}{\lambda_1}+k_1](https://tex.z-dn.net/?f=k_2%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda_2%7D%20-%5Cfrac%7Bhc%7D%7B%5Clambda_1%7D%2Bk_1)
Replacing with our values,
![k_2 = \frac{4.136*10^{-15}*3*10^17}{300} -\frac{4.136*10^{-15}*3*10^17}{640}](https://tex.z-dn.net/?f=k_2%20%3D%20%5Cfrac%7B4.136%2A10%5E%7B-15%7D%2A3%2A10%5E17%7D%7B300%7D%20-%5Cfrac%7B4.136%2A10%5E%7B-15%7D%2A3%2A10%5E17%7D%7B640%7D)
![k_2 = 2.19725+0.3](https://tex.z-dn.net/?f=k_2%20%3D%202.19725%2B0.3)
![k_2 = 2.49eV](https://tex.z-dn.net/?f=k_2%20%3D%202.49eV)
Therefore the maximum kinetic energy is 2.49eV
<em>Note: Speed of light is converted to nanometers. </em>
I think this solution is a supersaturated solution. This solution is called us such because the solute in this solution is more than the solvent can dissolve or the ammount of solute exceeds the solutbility of the solute in a particular solvent.