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3 years ago

A chloride ion, : Cl :i– , acts as a alternate base when it combines with

Chemistry

1 answer:

zysi [14]3 years ago

3 0

Answer:

Explanation:

The answer is D...and if you need explanation you can comment

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Find the theoretical oxygen demand for the

never [62]

Answer:

a) 213.3 mg/L

b) 62.61 mg/L

c) 0.0225 mg/L

Explanation:

Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products

a) Given:

Concentration of acetic acid, $[CH3COOH]$ = 200 mg/L

$CH3COOH + 2O2 \rightarrow 2CO2 + 2H2O$

$ThOD = \frac{mass\ O2}{mass\ CH3COOH} * conc. CH3COOH$

Based on the reaction stoichiometry:

mass of $CH3COOH$ = 60 g

mass of $O2$ = 2(32) = 64 g

$ThOD = \frac{64 g}{60 g} * 200mg/L = 213.3 mg/L$

b) Given:

Concentration of ethanol, $[C2H5OH]$ = 30 mg/L

$C2H5OH + 3O2 \rightarrow 2CO2 + 3H2O$

$ThOD = \frac{mass\ O2}{mass\ C2H5OH} * conc. C2H5OH$

Based on the reaction stoichiometry:

mass of $C2H5OH$ = 46 g

mass of $O2$ = 3(32) = 96 g

$ThOD = \frac{96 g}{46 g} * 30mg/L = 62.61 mg/L$

c) Given:

Concentration of sucrose, $[C12H22O11]$ = 50 mg/L

$C12H22O11 + 12O2 \rightarrow 12CO2 + 11H2O$

$ThOD = \frac{mass\ O2}{mass\ C22H22O11} * conc. C12H22O11$

Based on the reaction stoichiometry:

mass of $C12H22O11$ = 342 g

mass of $O2$ = 12(32) = 384 g

$ThOD = \frac{384 g}{342 g} * 50mg/L = 0.0225 mg/L$

7 0

3 years ago

One end of a molecule has a positive charge and the other end of the same molecule has a negative charge. What is the best term

klasskru [66]

An ion is an element that bears only one electric charge, either positive or negative. An isotope is an element with the same number of protons but a different number of neutrons. An electron is a negatively charged subatomic particle. A dipole fits the characteristics. Hence, the answer is B.

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3 years ago

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Light is released when an excited electron moves from higher energy level back down to its lower, more stable energy level. The

kolbaska11 [484]

A0 emission as there is an increase in energy

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3 years ago

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Find the molar mass of KC1

leonid [27]

$M_{KCl} = M_{K}+M_{Cl}=39.0983\frac{g}{mol}+35.453\frac{g}{mol}=74.5513\frac{g}{mol}$