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strojnjashka [21]
3 years ago
11

A chloride ion, : Cl :i– , acts as a alternate base when it combines with

Chemistry
1 answer:
zysi [14]3 years ago
3 0

Answer:

D

Explanation:

The answer is D...and if you need explanation you can comment

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Balanced equation for calcium carbonate and hydrobromic acid
Luda [366]

Answer:

2 HBr (aq) + CaCO3 (s) → CaBr2 (aq) + CO2 (g) + H2O (l)

3 0
3 years ago
When one of the atoms involved in a covalent bond has a much higher electronegativity than the other atom, what type of bond res
ICE Princess25 [194]
If electronegativity difference between atoms is much higher then they form ionic bond.

Hope this helps!
5 0
4 years ago
Photosynthesis allows plants to turn light energy into chemical energy by forming glucose from carbon dioxide and water: 6CO2(g)
dezoksy [38]

Answer:

305 g of CO₂

3.77 × 10⁵ kJ

Explanation:

Let's consider the global reaction for photosynthesis.

6 CO₂(g) + 6 H₂O(l) → C₆H₁₂O₆(g) + 6 O₂(g)  ΔHrxn = 2802.8 kJ

<em>A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?</em>

<em />

Let's consider the following relations:

  • The potato is 100%-73%=27% glucose by mass.
  • 1 lb = 453.59 g.
  • 6 moles of CO₂ produce 1 mole of glucose.
  • The molar mass of glucose is 180.156 g/mol.
  • The molar mass of carbon dioxide is 44.01 g/mol.

Then, for a 1.70 lb potato:

1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{6molCO_{2}}{1molGlucose} .\frac{44.01gCO_{2}}{1molCO_{2}} =305gCO_{2}

<em>How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?</em>

<em />

According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:

1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{2802.8kJ}{1molGlucose} .\frac{1}{0.86\% } =3.77\times 10^{5} kJ

7 0
3 years ago
The magnesium atom in chlorophyll A. is used to pass excited electrons on to pheophytin B. is coupled to the production of ATP C
goblinko [34]

Answer:

B. is coupled to the production of ATP

Explanation:

The magnesium in chlorophyll acts as an activator of enzymes associated with energy metabolism, especially respiratory enzymes and others that act on phosphorylated substrates such as ATP.

7 0
4 years ago
How do you find the average atomic mass?
grin007 [14]

To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.

6 0
3 years ago
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