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3 years ago

I ran across this symbol in some Electrical wiring documents and I am unaware of what this means. Any help?

Engineering

1 answer:

Minchanka [31]3 years ago

6 0

Answer:

Opened Push-button Switch (i.e. a PTM Switch)

Explanation:

Tha's just another symbol for a switch, but this one specifies that the switch is a push-button type of switch.

Since it's not touching and completing the line, the state of the switch is initially open.

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A 400 kg machine is placed at the mid-span of a 3.2-m simply supported steel (E = 200 x 10^9 N/m^2) beam. The machine is observe

Alenkinab [10]

Answer:

moment of inertia = 4.662 * 10^6 $mm^4$

Explanation:

Given data :

Mass of machine = 400 kg = 400 * 9.81 = 3924 N

length of span = 3.2 m

E = 200 * 10^9 N/m^2

frequency = 9.3 Hz

Wm ( angular frequency ) = 2 $\pi f$ = 58.434 rad/secs

also Wm = $\sqrt{\frac{g}{t} }$ ------- EQUATION 1

g = 9.81

deflection of simply supported beam

t = $\frac{wl^3}{48EI}$

insert the value of t into equation 1

W $m^2$ = $\frac{g*48*E*I}{WL^3}$ make I the subject of the equation

I ( Moment of inertia about the neutral axis ) = $\frac{WL^3* Wn^2}{48*g*E}$

I = $\frac{3924*3.2^3*58.434^2}{48*9.81*200*10^9}$ = 4.662 * 10^6 $mm^4$

6 0

3 years ago

The displacement volume of an internal combustion engine is 2.2 liters. The processes within each cylinder of the engine are mod

soldier1979 [14.2K]

Answer:

A) 14.75

B) 3.36Kj

C) 2384.2k

D) 117.6kW

E) 57.69%

Explanation:

Attached is the full solutions.

5 0

4 years ago

A hole of diameter D = 0.25 m is drilled through the center of a solid block of square cross section with w = 1 m on a side. The

attashe74 [19]

Answer:

$q=4.013\:\:kW\\\\T_1=278.91\:\:^{\circ}C\\\\T_2=275.82\:\:^{\circ}C$

Explanation:

$R_{conv,1}=(h_1\pi D_1L)^{-1}=(50*0.25*2)^{-1}=0.01273\:\:K/W\\\\R_{conv,2}=(h^2*4wL)^{-1}=(4*4*1)^{-1}=0.0625\:\:K/W\\\\R_{cond(2D)}=(Sk)^{-1}=(8.59*150)^{-1}=0.00078\:\:K/W$

So, heat rate can be calculated as follows:

$q=\frac{T_{\infty,1}-T_{\infty,2}}{R_{conv,1}+R_{conv,2}+R_{cond(2D)}} =\frac{330-25}{0.076} =4.013\:\:kW$

Surface temperatures can be calculated as follows:

$T_1=T_{\infty,1}-qR_{conv,1}=330-51.09=278.91\:\:^{\circ}C\\\\T_2=T_{\infty,2}+qR_{conv,2}=25+250.82=275.82\:\:^{\circ}C$

6 0

4 years ago

The size of an engine is called the engine

Stolb23 [73]

Answer:

Explanation:

I guess so

8 0

3 years ago

Read 2 more answers

25 gallons of an incompressible liquid exert a force of 70 lbf at the earth’s surface. What force in lbf would 6 gallons of this

jekas [21]

Answer:

froce by 6 gallon liquid on moon surface is 2.86 lbf

Explanation:

given data:

at earth surface

volume of an incompressible liquid = Ve = 25 gallons

force by liquid = 70 lbf

on moon

volume of liquid = Vm = 6 gallons

gravitational acceleration on moon is am = 5.51 ft/s2

Due to incompressibility , the density remain constant.

mass of liquid on surface of earth $= \frac{ force}{ acceleration}$

$mass = \frac{70lbf}{32.2 ft/s2}$

mass = 2.173 pound

$density \rho = \frac{mass}{volume}$

$= \frac{2.173}{25} = 0.0869 pound/ gallon$

froce by 6 gallon liquid on moon surface is

Fm = mass * acceleration

= density* volume * am

= 0.0869 *6* 5.51

= 2.86 lbf

5 0

3 years ago