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Anna71 [15]
2 years ago
10

Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmi

ssion axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 6.00?
Physics
1 answer:
Vladimir [108]2 years ago
7 0

Answer: 65.9^{\circ}

Explanation:

Given

Intensity must be reduced by a factor of 6

Intensity is given by I=I_o\cos ^2\theta\\

Substitute I by \frac{I_o}{6}

\Rightarrow \dfrac{I_o}{6}=I_o\cos ^2\theta\\\\\Rightarrow \cos^2\theta =\dfrac{1}{6}\\\\\Rightarrow \cos \theta=\dfrac{1}{\sqrt{6}}\\\\\Rightarrow \theta=65.9^{\circ}

So, the disk must be rotated by an angle of 65.9^{\circ} .

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Answer:

20.96 m/s^2 (or 21)

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Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

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