Answer:
Explanation:
Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.
Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.
When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.
One sodium and fluorine each totaling 2 atoms are enough to make the bond.
As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.
The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.
The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.
The name of the compound is sodium fluoride with formula NaF.
Answer:- 2.39 mL are required.
Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:
![M_1V_1=M_2V_2](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2)
Where,
and
are molarities of concentrated and diluted solutions and
and
are their respective volumes.
= 1.10M
= 5.00mM = 0.005M (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)
= ?
= 525 mL
Let's plug in the given values in the formula:
![1.10M(V_1)=0.005M(525mL)](https://tex.z-dn.net/?f=1.10M%28V_1%29%3D0.005M%28525mL%29)
![V_1=(\frac{0.005M*525mL}{1.10M})](https://tex.z-dn.net/?f=V_1%3D%28%5Cfrac%7B0.005M%2A525mL%7D%7B1.10M%7D%29)
![V_1=2.39mL](https://tex.z-dn.net/?f=V_1%3D2.39mL)
So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.
Answer :
(a) The speed in Km/hr is, ![10.8\times 10^8Km/hr](https://tex.z-dn.net/?f=10.8%5Ctimes%2010%5E8Km%2Fhr)
(b) The speed in mi/min is, ![1.125\times 10^7mi/min](https://tex.z-dn.net/?f=1.125%5Ctimes%2010%5E7mi%2Fmin)
Solution :
The speed of light = ![3\times 10^8m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8m%2Fs)
(a) Convert speed of light from m/s to Km/hr
![(3\times 10^8m/s)\times \frac{3600}{1000}=10.8\times 10^8Km/hr](https://tex.z-dn.net/?f=%283%5Ctimes%2010%5E8m%2Fs%29%5Ctimes%20%5Cfrac%7B3600%7D%7B1000%7D%3D10.8%5Ctimes%2010%5E8Km%2Fhr)
conversions used :
(1 Km = 1000 m)
(1 hr = 3600 sec)
(b) Convert speed of light from m/s to mi/min
![(3\times 10^8m/s)\times \frac{60}{1600}=1.125\times 10^7mi/min](https://tex.z-dn.net/?f=%283%5Ctimes%2010%5E8m%2Fs%29%5Ctimes%20%5Cfrac%7B60%7D%7B1600%7D%3D1.125%5Ctimes%2010%5E7mi%2Fmin)
conversions used :
![(1m=\frac{1}{1609.34}mile)\\\\(1sec=\frac{1}{60}min)](https://tex.z-dn.net/?f=%281m%3D%5Cfrac%7B1%7D%7B1609.34%7Dmile%29%5C%5C%5C%5C%281sec%3D%5Cfrac%7B1%7D%7B60%7Dmin%29)
Answer:We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
XeF₆
Explanation:
Hi there!
• Avogadro's number = 6.023 × 10²³
• No.of molecules in N = 1.806 × 10²² [ Given ]
It's known that :-
Number of molecules = Moles × Avogadro's number
=> 1.806 × 10²² = Mol. × 6.023 × 10²³
=> Mole =
![\dfrac {1.806 \cdot 10^{22} }{6.023 \cdot 10^{23} }](https://tex.z-dn.net/?f=%5Cdfrac%20%7B1.806%20%5Ccdot%2010%5E%7B22%7D%20%7D%7B6.023%20%5Ccdot%2010%5E%7B23%7D%20%7D)
=> Moles = 0.03 mol.
Hence, 0.03 mol. is th' required answer.
~ Hope it helps!