Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You
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Answer:
Explanation:
When the object fall from the top floor it moves with parabolic motion.
This particular case is a horizontal motion of a projectile, so the equation that relates the distance and the time in the y-axes is:
Here: y is the final height, it will be 0, because the object touch the ground.
y₀ is the initial height, it will be h and v₀ in y-axis is zero, because it has a horizontal initial velocity.
So we have:
(1)
We know that the velocity at the x-axes remains constant, then we have:
x is the distance from the base of the building
we can solve it for t and put on (1).
Solving it for x we will have:
But
I hope it helps you!