Just multiply the "1.0 m/s" by ' 1 ' a few times. (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)
(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =
(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =
(3,600 / 1,000) (km / hr) =
3.6 km/hr .
Weight is the measurement of the pull of gravity on an object, while mass is the measurement of the amount of matter that an object contains.
Answer:
The change of the volume of the device during this cooling is 
Explanation:
Given that,
Mass of oxygen = 10 g
Pressure = 20 kPa
Initial temperature = 110°C
Final temperature = 0°C
We need to calculate the change of the volume of the device during this cooling
Using formula of change volume


Put the value into the formula



Hence, The change of the volume of the device during this cooling is 
The answer is c. it requires no works
Answer:
Rs. 432*10^3 (In kilowatts per hour)
I hope it will be useful.