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sergejj [24]
3 years ago
6

0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC.

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

  • so, V= (0.45)(0.08206)(348) / 3.00
  • = 4.284 L
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