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sergejj [24]
3 years ago
6

0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC.

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

  • so, V= (0.45)(0.08206)(348) / 3.00
  • = 4.284 L
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There is only one significant figure in the provided number 0.06. The decimal place of the first digit is indicated by the zeros that appear to the right of the decimal point but before the first non-zero digit.

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<u>Dehydration reaction of 2-methyl-2-pentanol</u> gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.

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