You can work these in your head if you consider the revenue generated by the least contributor (children's tickets) and the difference in revenue between that and the larger contributor ($2.00 -1.50 = 0.50).
If all were children's tickets, the revenue would be 500*$1.50 = $750.00. The actual revenue exceeded that amount by $862.50 -750.00 = 112.50. This difference in revenue is made up by the sale of $112.50/$0.50 = 225 adult tickets. Then the number of children's tickets is 500 -225 = 275.
225 adult tickets were sold
275 children's tickets were sold.
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If you need an equation, you can write an equation using a variable for the number of adult tickets sold (the largest contributor).
.. (500 -a)*1.50 +a*2.00 = 862.50
.. 0.50a = (862.50 -750.00) . . . . . does this look familiar, yet?
.. a = 112.50/0.50 = 225
First subtract three from both sides. then you have
+2x=-3 and you solve from there
Answer:
3x + 100 < 2x - 250
Step-by-step explanation:
The problem said that Keisha's guess was "250 less than twice the number".
It was written as 250-2x, which is actually twice the number less than 250, because we are subtracting 2x. We just need to write it like this:
2x-250
So the inequality should be:
3x + 100 < 2x - 250
