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Kisachek [45]
3 years ago
14

<Q and <R are complementary angles. If m<Q = (31 - 3x)° and m<R = (19x - 5)°, find m<R​

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

31-3x+19x-5=90

26+16x=90

-26 -26

--------------------

16x= 64

16x/16= 64/16

x=4

m <R=19 (4)-5= 71.

sergiy2304 [10]3 years ago
6 0

Answer:

Step-by-step explanation:

90=(31-3x)+(19x-5)

90=31-3x+19x-590=19x-3x+31-5

90=16x+26

90-26=17x

64=4x

x=4

m∠R=19(4)-5

m∠R=76-5

m∠R=71

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This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

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1 year ago
you are to give a client one tablet labeled 0.15 mg and one labeled 0.025 mg. what is the total dosage of these two tablets
Ivenika [448]
Simply add the two dosages together, (0.15+0.025) and the answer is 0.175 :)
7 0
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12) Josh has $252 in his bank account. This is $12 more than 6 times the amount of money
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Answer:

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Step-by-step explanation:

(252-12)/6=40

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Answer:

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Step-by-step explanation:

27kg × 1000 = 27,000g

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Sphinxa [80]
I got B but I'll show you how I got that answer.

Let's look at AB and BC. AB = 3 and BC = 4.
3/4 = 0.75

On the triangle, AB = 90. And BC = 10x - 20. We need to solve for x and prove that AB/BC = 0.75.

Let's start with Choice A.

10(11) - 20 = 90.

AB = 90
BC = 90.

90/90 = 1. It doesn't equal 0.75. Meaning this answer is wrong.

Now let's look at Choice B.

10(14) - 20 = 120.

AB = 90
BC = 120

90/120 = 0.75

So, 3:4 = 90:120 making Choice B the correct Answer. Let me know if this is correct
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