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Vera_Pavlovna [14]
2 years ago
14

An 11.8 eV photon is absorbed by an electron in an atom, causing the electron to be excited from level 1 to level 3. The electro

n then emits a 4.1 eV photon and shifts to level 2. What photon will be emitted when the electron moves back to level 1?
a. 15.9 eV
b. 11.8 eV
c. 7.7 eV
d. 4.1 eV
Physics
1 answer:
densk [106]2 years ago
6 0

Answer:

c. 7.7 eV

Explanation:

The computation of the photon emitted is shown below:

Given that

From level 1 to level 3, the energy absorbed by electrons is 11.8eV

And, when from level 3 to level3, the energy released by electron is 4.1eV

So, from level 2 to level 1, the energy released is

= 11.8 - 4.1

= 7.7

= 7.7eV

Hence, the third option is correct

The same is to be considered

And, the other options are wrong

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A thin, light wire 75.2 cm long having a circular cross section 0.560 mm in diameter has a 25.2 kg weight attached to it, causin
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Answer:

The stress is calculated as 1.003\times 10^{9}\ Pa

Solution:

As per the question:

Length of the wire, l = 75.2 cm = 0.752 m

Diameter of the circular cross-section, d = 0.560 mm = 0.560\times 10^{- 3}\ m

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Elongation in the wire, \Delta l = 1.10\ mm = 1.10\times 10^{- 3}\ m

Now,

The stress in the wire is given by:

Stress,\ \sigma = \frac{Force,\ F}{Area,\ A}          (1)

Now,

Force is due to the weight of the attached weight:

F = mg = 25.2\times 9.8 = 246.96\ N

Cross  sectional Area, A = \pi (\frac{d}{2})^{2} = \pi (\frac{0.560\times 10^{- 3}}{2})^{2} = 2.46\times 10^{- 7}\ m^{2}

Using these values in eqn (1):

\sigma = \frac{246.96}{2.46\times 10^{- 7}} = 1.003\times 10^{9}\ Pa  

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Does anyone know the answer
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The sound mixer will need to increase the amplitude of the sound wave produced by the singer which will increase the loudness of the sound.

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The amplitude of a sound wave is the maximum vertical displacement of the sound wave.

The sound mixer will need to increase the amplitude of the sound wave produced by the singer.

The increase in the amplitude of the sound wave produced by the lower tune singer will result in increased loudness of the sound.

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