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Marrrta [24]
3 years ago
6

Oxygen Supply in Submarines Nuclear submarines can stay under water nearly indefinitely because they can produce their own oxyge

n by electrolysis of water.
How many liters of O2 at 298 K and 1.00 bar are produced in 1.00 hr in an electrolytic cell operating at a current of 0.0200 A?
Physics
1 answer:
gregori [183]3 years ago
5 0

Answer:

1.865 * 10^-4 L

Explanation:

The equation of the reaction is:

4OH^-(aq) ----->2H2O(l) + O2(g) + 4e

Since one mole of oxygen which occupies 22.4 L is produced in the electrolysis of water by 4 Faraday of electricity as shown in the equation above;

Then;

4 * 96500 C liberates 22.4 L of oxygen

60 * 60 * 0.0200 C will liberate 60 * 60 * 0.0200 *  22.4/4 * 96500

= 1.865 * 10^-4 L

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Answer: 2 significant figures in 6.4

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.

All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.

All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

Mass of beaker = 24.2 g

Mass of beaker + mass of water = 30.625 g

Mass of water = 30.625 - Mass of beaker = 30.625 - 24.2 = 6.4g

The rule apply for the addition and subtraction is :

The answer would contain same number of decimal places as there are in the least precise number present.

Thus there are 2 significant figures in mass of water which is 6.4 grams.

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