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3 years ago

Why isnt water on the periodic table?

Chemistry

1 answer:

Oksana_A [137]3 years ago

8 0

Answer:

Because its not a pure substance. It is a combination of pure substances.

Explanation:

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Which factor most likely facilitates mass movement after heavy rains in a dry region?

melomori [17]

Answer: Option (b) is the correct answer.

Explanation:

The process in which sediment moves downhill is known as mass movement.

Different types of mass movement are landslides, mud slides, slump, creep etc.

Mud flow contains mass of saturated rock particles of all sizes. Mud flow arises due to sudden flood of water or due to heavy rain in a dry region (semi-arid region). Soil and rocks from a large slope area flow along with the flood water and gets washed to a gulch or canyon.

As a result, debris and water moves down canyon and lay out on the gentle slopes below.

Thus, we can conclude that mud flow is most likely facilitates mass movement after heavy rains in a dry region.

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3 years ago

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When a ball is rolling down a hill, what forces are acting on the ball? Why does it speed up?

Margaret [11]

Answer:gravity

Explanation:

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3 years ago

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The rotational period of the moon is_____

Ivahew [28]

Answer:

Hi, I think the D since the moon rotates about once a month and these months have different amounts of days. an example would be February that can have like 28 or 29 in leap year

Explanation:

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3 years ago

Most of the volume of a gas is

Vesna [10]

Answer:

One mole of any gas has a volume of 24 dm3 or 24,000 cm3 at rtp (room temperature and pressure).

Explanation:

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3 years ago

A 3.4 g sample of an unknown monoprotic organic acid composed of C,H, and O is burned in air to produce 8.58 grams of carbon dio

Pavlova-9 [17]

Answer:

$C_7H_6O_2$

Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

(1) In this case, since 8.58 g of carbon dioxide are released, we can first compute the moles of carbon in the compound:

$n_C=8.58gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.195molC$

And the moles of hydrogen due to the produced 1.50 grams of water:

$n_H=1.50gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O} =0.166molH$

Next, to compute the mass and moles of oxygen, we need to use the initial 3.4 g of the acid:

$m_O=3.4g-0.195molC*\frac{12.01gC}{1molC}-0.166molH*\frac{1.01gH}{1molH} =0.89gO\\\\n_O=0.89gO*\frac{1molO}{16.0gO}=0.0556molO$

Thus, the subscripts in the empirical formula are:

$C=\frac{0.195}{0.0556}=3.5 \\\\H=\frac{0.166}{0.0556}=3\\\\O=\frac{0.0556}{0.0556}=1\\\\C_7H_6O_2$

As they cannot be fractions.

(2) In this case, since the acid is monoprotic, we can compute the moles by multiplying the concentration and volume of KOH:

$n_{KOH}=0.279L*0.1mol/L\\\\n_{KOH}=0.0279mol$

Which are equal to the moles of the acid:

$n_{acid}=0.0279mol$

And the molar mass:

$MM_{acid}=\frac{3.4g}{0.0279mol} =121.86g/mol$

(3) Finally, since the molar mass of the empirical formula is:

7*12.01 + 6*1.01 + 2*16.00 = 122.13 g/mol

Thus, since the ratio of molar masses is 122.86/122.13 = 1, we infer that the empirical formula equals the molecular one:

$C_7H_6O_2$

Best regards!

8 0

3 years ago