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sergejj [24]
3 years ago
5

The element magnesium has significantly fewer protons and neutrons than gold. If you were to use MgMg in place of AuAu in the Ru

therford experiment, how would you predict the results from the experiment to change?
Chemistry
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:The center will be quite smaller in magnesium than in gold thus the alpha particle will scatter to a lesser degree and the experiment may not yield a meaningful result.

Explanation:

Gold has seventy nine protons and magnesium has only twelve protons. Gold atoms are quite much more massive than magnesium atoms. This implies that if magnesium atoms were used in Rutherford's experiment, the number of protons will be too few to give a reasonable result since the atom is quite small. A larger atom, having a larger centre is required in order to have meaningful scattering of alpha particles.

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Pluto is a planet<br><br> True<br> False
koban [17]

Answer:

False

Explanation:

It's classified as a dwarf planet, but not technically a planet.

6 0
3 years ago
How do electrons differ from protons and neutrons? A. They do not move. B. They are larger. C. They are not in a fixed position.
nikdorinn [45]
Hi!

Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus. 

With this in mind, the answer will be C.

Hopefully, this helps! =)
4 0
3 years ago
Read 2 more answers
Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i
swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg  

7 0
3 years ago
Plz help me guys for 20 points 5th GRADE SCEINCE
Usimov [2.4K]
Option 3 using forest land to build homes
3 0
3 years ago
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For each situation below, state whether water will move into the cell, move out of the cell, or stay the same.
Firdavs [7]
Water moves from an area of higher water potential (aka. "more water" in simple language) to an area of lower water potential (aka. "less water" in simple language).

For A, cells in carrots have water stored in their cytoplasm, where many soluble substances may be found (e.g. sodium ions). On the other hand, pure water has no other soluble substances other than the water molecules (I.e. H2O). Pure water will thus have a higher water potential as compared to the water in carrot cells, and so, water will move from pure water into the carrot cells via osmosis down a concentration gradient.

B. Corn syrup is water that has high concentrations of sugars, thus it is very likely to have a lower water potential than the cells of carrots. Water will move from within the cells of carrots and out to the corn syrup, down a concentration gradient.

C. The water in carrot cells will stay the same, since carrot cells have the same water potential as the surrounding solution which has the same water potential as cytoplasm.

Hope this helps! :)
8 0
3 years ago
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