nabr + cacl2 are the products
Answer:
Option B. 10
Explanation:
If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.
(number of atoms / NA)
6.02 x 10²³ atoms ___ 1 mol
6×10²⁴ atoms will occupy (6×10²⁴ / NA) = 9.96 moles
H, has 10 moles in the butano formula.
Answer:
3H2SO4 + 2B(OH)3 -> B2(SO4)3 + 6H2O
Explanation:
I believe it would be better to use an orbital designation than the written configuration, if the number of electrons in the ground state of the atom are quite high for the given element, as above 50, for instance.
This saves space and also one can see the discrete quantized energy levels associated with the subshells of the main energy levels if written in orbital designation.
The balanced equation:
Mg+2HCl⇒ MgCl₂+H₂