5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
Answer:
by principal quantum number (n) and azimuthal quantum number (l)
Explanation:
I used the web to answer so I'm not sure if this is right
Answer:
pressure of the oxygen gas is 7.88atm
Explanation:
Moles of oxygen in cylinder = 2.80 mol
volume=8.58L
temperature=294K
molar gas constant(R)= 0.0821 L atm / (mol K)
The pressure is calculated using ideal gas law:
PV = nRT
making Pressure subject of the formula
P
=
nRT
/V
=
2.80× 0.0821 ×294 /8.58 L
P = 7.88 atm
