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3 years ago

How are humans activity contributing to climate change?

Chemistry

2 answers:

Dmitry [639]3 years ago

5 0

Driving as well as deforestation is contributing to climate change

ad-work [718]3 years ago

4 0

Answer:

Some human activities that contribute to climate change would be fracking, driving vehicles, deforestation, and developing cities. Fracking releases methane and other greenhouses gases into the atmosphere. Driving vehicles, like cars or trains, also releases carbon dioxide into the atmosphere. Deforestation decreases the amount of oxygen being produced. Developing cities also contributes because it consumes almost 80% of the world's energy, as well as producing 60% of the greenhouse gases.

You might be interested in

Which of the following uses the relationship between the DNA of various groups of organisms to determine how long ago they diver

Triss [41]

Molecular clocks because the m<span>easure changes in DNA or proteins to indicate degrees of relationship among species.Molecular clocks, together with evidence from the fossil record, allows scientists to estimate how long ago various groups of organisms diverged evolutionarily from one another</span>

4 0

3 years ago

A metallic bond can exist between atoms that have low ionization energies and

zavuch27 [327]

Answer: The elements that have the lowest electronegativity are the VIII A elements or noble gases. These elements have a theoretical electronegativity of zero. These elements are stable in their electron configuration there is not force moving the noble gases to gain any electrons.

Explanation:

7 0

3 years ago

Calculate the inner diameter of the steam tube between the boiler and the high pressure turbine if the average velocity of the s

stich3 [128]

Answer:

The inner diameter of the steam tube is 0.1185 m.

Explanation:

$m=\rho \times A\times v=\frac{1}{V}\times A\times v$

m = mass flow rate

$\rho$ = density of the liquid

V=specific volume = $\frac{1}{\rho }$

v = velocity of the liquid

A = area of cross-section

Diameter of the cross-section = d = 2r

Given: m = 18 kg/s, v = 60 m/s,A=?, $V = 0.036793 m^3/kg$

$18 kg/s=\frac{1}{0.036793 m^3/kg}\times A\times 60 m/s$

$A=0.0110379 m^2$

Area of the inner cross section = $\pi r^2=\pi \frac{d^2}{4}$

$\pi \frac{d^2}{4}=0.0110379 m^2$

d = 0.1185 m

The inner diameter of the steam tube is 0.1185 m.

5 0

4 years ago

A mixture of sodium chloride (salt) and water is heated until only a

mojhsa [17]

Answer:

B.evaporation hope it is helpful

Explanation:

it is evaporation because it is bwing heated

4 0

2 years ago

The theoretical yield of NaBr from

Lapatulllka [165]

Taking into account definition of percent yield, the percent yield for the reaction is 100%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 FeBr₃ + 3 Na₂S → Fе₂S₃ + 6 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

FeBr₃: 2 moles
Na₂S; 3 moles
Fе₂S₃: 1 mole
NaBr: 6 moles

<h3>Moles of NaBr formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 2 moles of FeBr₃ form 6 moles of NaBr, 2.36 moles of FeBr₃ form how many moles of NaBr?

$moles of NaBr=\frac{2.36 moles of FeBr_{3}x6 moles of NaBr }{2 moles of FeBr_{3}}$

moles of NaBr= 7.08 moles

Then, 7.08 moles of NaBr can be produced from 2.36 moles of FeBr₃.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

$percent yield=\frac{actual yield}{theorical yield}x100$

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield for the reaction in this case</h3>

In this case, being the molar mass of NaBr 102.9 g/mole, you know: