Answer:
Empirical formula of compound is C₄H₈O
Explanation:
Given data:
Mass of compound = 5.60 g
Mass of CO₂ = 13.7 g
Mass of H₂O = 5.60 g
Empirical formula of compound = ?
Solution:
Percentage of C:
13.7 g/5.60 g × 12/44× 100
2.45×0.273× 100 = 66.9%
Percentage of H:
5.60 g/ 5.60 g × 2.016/18 × 100
11.2%
Percentage of O:
(66.9% + 11.2%) - 100 = 21.9%
Grams atom of C , H, O
66.9/12 = 5.6
11.2 / 1.008 = 11.11
21.9 / 16 = 1.4
Atomic ratio:
C : H : O
5.6/1.4 : 11.11/1.4 : 1.4/1.4
4 : 8 : 1
Empirical formula:
C₄H₈O
Answer:
1) 7.256 mol Br2 (Cl2)/(Br2)
The Br2 cancels out, so we have 7.256(2)
This is 14.512.
2) Number of moles = mass / molar mass
Number of moles = 239.7 g/ 35.5 g/mol
Number of moles = 6.8 mol
BrCl=13.6 mol
13.6(11.5.357)
1568.9 g
3) Repeat the same process with problem 2, given that there are 6.022x10^23 atoms in a mole.
Explanation:
Br2 + Cl2 → 2BrCl
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Answer:
V₂ = 0.98 L
Explanation:
Given data:
Initial volume = 750 mL =0.75 L
Initial pressure = 745 mmHg (745/760 =0.98 atm)
Initial temperature = 25 °C (25 +273 = 298 K)
Final temperature = -35°C (-35+273 = 238 K)
Final volume = ?
Final pressure = 0.60 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 0.98 atm × 0.75 L × 238 K / 298 K × 0.60 atm
V₂ = 174.93 atm .L. K / 178.8 K.atm
V₂ = 0.98 L