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andreev551 [17]
3 years ago
15

What is the pH of a 1.0 x 10-4 M solution of KOH?

Chemistry
1 answer:
Svetach [21]3 years ago
7 0

Answer:

pH = 10

Explanation:

KOH is a strong base; thus it will completely dissociate:

KOH -> K⁺ + OH⁻

Since it completely dissociates, the concentration of both K⁺ and OH⁻ will be the concentration of KOH given (1.0 x 10^-4 M).

We can then find pOH by taking the negative log of the OH⁻, or hydroxide, concentration:

pOH = -log[OH⁻] = -log[1.0 x 10^-4 M] = 4

At 25 degrees Celsius, pH + pOH = 14. If we solve for pH and then plug in our pOH, we get:

pH = 14 - pOH = 14 - 4 = 10

The pH of a 1.0 x 10^-4 M solution of KOH is thus 10.

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