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3 years ago

State two reasons why the rod is not in equilibrium

Physics

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

Answer:

For equilibrium the net torque on the rod must be zero. So the 100N forces should on either side of the pivot point i.e. one on the left and one the right, and in same direction.

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The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -41 oC and 900 Pa, respect

Fittoniya [83]

Answer:

Part a)

$\rho = 0.0205 kg/m^3$

Part b)

$\rho = 1.22 kg/m^3$

So density of atmosphere at Martian Surface is very less than the density at Earth.

Explanation:

Part a)

As per ideal gas equation we know that

$PM = \rho RT$

here we know that Martian atmosphere is equivalent to that of carbon

so we will have

$P = 900 Pa$

$T = 273 - 41 = 232 K$

now we will have

$(900)(0.044) = \rho (8.31)(232)$

$\rho = 0.0205 kg/m^3$

Part b)

Now for the earth surface the density of air is given for

$P = 101.6 kPa$

$T = 18 ^oC$

so we will have

$PM = \rho RT$

$(101.6\times 10^3)(0.029) = \rho(8.31)(273 + 18)$

$\rho = 1.22 kg/m^3$

So density of atmosphere at Martian Surface is very less than the density at Earth.

8 0

2 years ago

A crate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.50m/s . The pulling force is 100 N parallel to t

sergey [27]

167.67 Joules of work are done by the gravitational force on the crate.

Force is defined as the product of the mass of the object and acceleration. The SI unit of the force of Newton.

Gravitational force is the force applied by gravity on an object. The gravity of the earth is 9.8 m/s².

Force = Mass × Acceleration

F = m × a

Mass of the crate = 10 kg

The initial speed of the crate = 1.50 m/s

The pulling force = 100 N

Horizontal angle made by the crate = 20 °

Coefficient of kinetic friction = 0.400

The crate is pulled to a height of 5 m.

$Sin θ= \frac{height}{distance}$

$= \frac{h}{d}$

$h = dSin θ$

Work done by the gravitational force on the crate is,

Work done by gravitational force = mass × gravity × height

$W_{g} = mgh$

$W_{g} = m \times g \times d \times sinθ$

$= 10 \times 9.8 \times 5 \times sin20°$

$= 167.67 \: J$

Therefore, 167.67 Joules of work is done by the gravitational force on the crate.

To know more about force, refer to the below link:

brainly.com/question/13191643

#SPJ4

5 0

1 year ago

What happens when electromagnetic waves cause a disturbance in electric

Leviafan [203]

Answer:

Explanation:

just answered it

7 0

2 years ago

A skater makes one revolution per second, f = w/(2p) = 1, with her arms and leg stretched (left). By lowering her leg and bringi

Firlakuza [10]

Answer:

Answer is given in the attachment.

Explanation:

Download pdf

4 0

3 years ago

Read 2 more answers

A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th

Marina CMI [18]

Answer:

The radius of the curve is 9,183.67 m.

Explanation:

Given;

velocity of the jet plane, v = 600 m/s

acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²

The radius of the curve is calculated from centripetal acceleration formula as given below;

$a = \frac{v^2}{r} \\\\r = \frac{v^2}{a} \\\\r = \frac{600^2}{39.2} \\\\r = 9,183.67 \ m$

Therefore, the radius of the curve is 9,183.67 m.

3 0

3 years ago

State two reasons why the rod is not in equilibrium​

State two reasons why the rod is not in equilibrium