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alina1380 [7]
3 years ago
13

State two reasons why the rod is not in equilibrium​

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

For equilibrium the net torque on the rod must be zero. So the 100N forces should on either side of the pivot point i.e. one on the left and one the right, and in same direction.

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Energy travels at right angles to the direction of the vibrating particles in ________ waves.
marshall27 [118]

Energy travels at right angles to the direction of the vibrating particles in Transverse waves

<h3>What is a transverse wave oceanography?</h3>

Energy can flow from one spot to another in a wave phenomenon, but the particles of matter in the medium return to their fixed position. A wave transmits energy without moving mass. Although waves can be observed moving through an ocean or lake, the water always returns to its resting place. The medium's particles just vibrate in situ. As they vibrate, the energy of the disturbance is passed on to the particles next to them, who then pass it on to the particles next to them, and so on.

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2 years ago
A car in front of the school goes from rest to 5.6 m/s in 3 seconds. What is its acceleration?
Nostrana [21]
I’m so so so so sorry I don’t know
4 0
4 years ago
Spymaster Paul, flying a constant 215km/h horizontally in a low-flying helicopter, want to drop secret documents into his contac
aleksandrvk [35]

Answer:

\theta = 49.56 degree

Explanation:

Relative horizontal velocity of plane with respect to the car is given as

v_r = v_p - v_c

so we have

v_p = 215 km/h

v_c = 155 km/h

now we have

v_r = 215 - 155

v_r = 60 km/h

v_r = 16.67 m/s

Now time taken by the object to drop the vertical height is given as

y = \frac{1}{2}gt^2

78 = \frac{1}{2}(9.81)t^2

t = 3.98 s

so the distance of the car must be

d = v_r\times t

d = 16.67 \times 3.98

d = 66.47 m

Angle of the car with horizontal is given as

tan\theta = \frac{y}{x}

tan\theta = \frac{78}{66.47}

\theta = tan^{-1}(1.17)

\theta = 49.56 degree

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3 years ago
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The time it will take him to fall can be found from:-3m = -(g*t^2)/2
Find that time, it's the time the horse will travel horizontal while the cowboy is falling.So the horizontal distance away is  10 m/s * t
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3 years ago
Select the correct images.
Afina-wow [57]

It could be the third and the first one.

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3 years ago
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