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maw [93]
3 years ago
11

How many milliliters of 12.0 m hcl(aq) are needed to prepare 905.0 ml of 1.00 m hcl(aq)?

Chemistry
1 answer:
givi [52]3 years ago
5 0
The  ml  of  12.0 M HCL  needed  to  prepare  905.0 ml  of 1.00m hcl   is  calculated  using   M1V1 =M2V2  formula
M1=  12.0 M
V1=?
M2= 905.0 ml
V2 = 1.00M

V1  is  therefore =  M2V2/M1

=905  x  1.00/12.0 = 75.42 ml

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Answer:

22.6According to the law of conservation of mass, the total mass of reactants should be equal to the total mass of products. Here, total mass of reactants= 11.3+11.3=22.6

•

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4 0
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A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com
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