How many milliliters of 12.0 m hcl(aq) are needed to prepare 905.0 ml of 1.00 m hcl(aq)?

1 answer:

5 0

The ml of 12.0 M HCL needed to prepare 905.0 ml of 1.00m hcl is calculated using M1V1 =M2V2 formula
M1= 12.0 M
V1=?
M2= 905.0 ml
V2 = 1.00M

V1 is therefore = M2V2/M1

=905 x 1.00/12.0 = 75.42 ml

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