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Darina [25.2K]
3 years ago
8

How can you drop two eggs the fewest amount of times, without them breaking?

Engineering
1 answer:
qwelly [4]3 years ago
7 0
You can use like a thickish paper but not to heavy and do it spiral and fall it with bubble paper and light things and then you spin it while you drop and it won’t crack
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In a vapor-compression refrigeration cycle, ammonia exits the evaporator as saturated vapor at -10°C. The refrigerant enters the
sergij07 [2.7K]

Answer:  (a) 0,142 (b) 52.99 (c) 2.83 (d) 88.26

Explanation:

If the refrigarating capacity is 150kw

(a) the mass flow rate of refrigerant, in kilograms per second  is 0.142

(b) the power input to the compressor, in kilowatts is 52.99

(c) the coefficient of performance is 2.83

(d) the isentropic compressor efficiency is 68.6 per cent

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3 years ago
How do heat and our use of electricity affect our daily activities and the environment
Andrews [41]

Answer:

there hope it can help.......

3 0
2 years ago
A disc brake rotor is being machined. Technician A says that a feed rate of 0.0008 inch per revolution and 150 RPM is where the
erma4kov [3.2K]

Answer:

Technician B only

Explanation:

During rotor reconditioning, which is the process also known as machining and sanding, where sanding is the involves the application of between 120 and 150 grit sandpaper while using a non-excessive force that is applied non-directionally for up to 60 seconds on each side such that the surface roughness meets OE standards. The rotors are then cleaned by washing after they are serviced before they can then be installed.

3 0
3 years ago
Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
3 years ago
Both model building codes and NFPA __________ can be used to determine the type of construction used in a building.
Alex777 [14]

Answer:

Both model building codes and NFPA 220 can be used to determine the type of construction used in a building.

8 0
3 years ago
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