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gtnhenbr [62]
3 years ago
12

Aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine .

Chemistry
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Explanation:

Let's consider the unbalanced equation that occurs when aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine. This is a single displacement reaction.

NaBr(aq) + Cl₂(g) ⇒ NaCl(aq) + Br₂(l)

We will start balancing Cl atoms by multiplying NaCl by 2.

NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Then, we get the balanced equation by multiplying NaBr by 2.

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

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