Question

Aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine .

Answer 1

Answer:

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Explanation:

Let's consider the unbalanced equation that occurs when aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine. This is a single displacement reaction.

NaBr(aq) + Cl₂(g) ⇒ NaCl(aq) + Br₂(l)

We will start balancing Cl atoms by multiplying NaCl by 2.

NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Then, we get the balanced equation by multiplying NaBr by 2.

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)