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mash [69]
3 years ago
14

Directions: Summarize the main ideas of this lesson by answering the question below.

Physics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

Explanation:

Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...

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The average resistivity of the human body (apart from surface resistance of the skin) is about 5.0 Ωm. The conducting path betwe
Iteru [2.4K]

Answer with Explanation:

We are given that

Resistivity,\rho=5\Omega m

Length of cylinder,l=1.6 m

Diameter ,d=0.10 m

Radius,r=\frac{d}{2}=\frac{0.10}{2}=0.05 m

a.Resistance,R=\frac{\rho l}{A}

R=\frac{5\times 1.6}{\pi(0.05)^2}=1.02\times 10^3\Omega

b.Current,I=100 mA=100\times 10^{-3} A

1 mA=10^{-3} A

Potential difference,V=IR

V=100\times 10^{-3}\times 1.02\times 10^3=102 V

5 0
3 years ago
A 0.050 kg metal bolt is heated to an unknown initial temperature. It is then dropped into calorimeter containing 0.15 kg of wat
Pachacha [2.7K]

The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

  • Mass of water (M) = 0.15 Kg
  • Initial temperature (T₁) = 21 °C
  • Final temperature (T₂) = 25 °C
  • Change in temperature (ΔT)  = T₂ – T₁ = 25 – 21 = 4 °C
  • Specific heat capacity of water (C) = 4184 J/KgºC
  • Heat absorbed (Q) =?

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

  • Heat absorbed by water = 2510.4 J
  • Heat released by metal (Q) = –2510.4 J
  • Mass of metal (M) = 0.050 Kg
  • Final temperature (T₂) = 25 °C
  • Specific heat capacity of metal (C) = 899 J/Kg°C
  • Initial temperature (T₁) =?

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

Learn more about heat tranfer:

brainly.com/question/26034272

7 0
3 years ago
A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic
Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

\epsilon=Blv\sin\theta

Here,

\theta is the angle between magnetic field and the wire’s velocity

\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0
3 years ago
The population of oak trees in a forest ecosystem is decreasing. The population of squirrels will most likely _____.
kondor19780726 [428]
The answer should be ''Decrease'' to fill in the blank because squirrels usually live in trees and get food from there so without a place to live when its raining and no food to survive, than they would die and lessen their population so that's why decrease is the answer.
7 0
3 years ago
What are the two main processes carried out by the excretory system?​
Paha777 [63]
Water and carbon dioxide
5 0
4 years ago
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