True. If the amount displaced is more than the mass, it floats. If the amount is less than the mass, it will sink.
(a) The work done by the applied force is 26.65 J.
(b) The work done by the normal force exerted by the table is 0.
(c) The work done by the force of gravity is 0.
(d) The work done by the net force on the block is 26.65 J.
<h3>
Work done by the applied force</h3>
W = Fdcosθ
W = 14 x 2.1 x cos25
W = 26.65 J
<h3>
Work done by the normal force</h3>
W = Fₙd
W = mg cosθ x d
W = (2.5 x 9.8) x cos(90) x 2.1
W = 0 J
<h3>Work done force of gravity</h3>
The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.
<h3> Work done by the net force on the block</h3>
∑W = 0 + 26.65 J = 26.65 J
Thus, the work done by the applied force is 26.65 J.
The work done by the normal force exerted by the table is 0.
The work done by the force of gravity is 0.
The work done by the net force on the block is 26.65 J.
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Solution :
Given data is :
Density of the milk in the tank, 
Length of the tank, x = 9 m
Height of the tank, z = 3 m
Acceleration of the tank, 
Therefore, the pressure difference between the two points is given by :
Since the tank is completely filled with milk, the vertical acceleration is 
Therefore substituting, we get
Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.
I’m pretty sure the answer is C. Any change of state or movement requires energy
