Answer:
The ramp lands at an horizontal distance of 3.989 m
Explanation:
Range: Range is defined as the horizontal distance of a projectile from the point of projection to the point where the projectile hits the projection plane again. It is measure in meters (m)
R = U²sin2∅/g..................................... Equation 1
Where R = The horizontal distance from the end of the ramp, U = rider's speed, ∅ = the ramp's angle to the horizontal.
<em>Given: U = 6.3 m/s, ∅ = 40°, g = 9.8 m/s²</em>
<em>Substituting these values into equation 1</em>
<em>R = [6.3²sin2(40)]/9.8</em>
<em>R = (39.69×sin80)/9.8</em>
<em>R = 39.69×0.985/9.8</em>
R = 3.989 m
Thus the ramp lands at an horizontal distance of 3.989 m
247.11 Kelvin, you have to convert the 34 Fahrenheit to get to the answer that you need.
Answer:
The answers are:
T, T, F, F, T, T, F, F, T, T, F
Good luck!
a) 
, 
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
is the gain in height of the student
For the first student, 
, so the work done is
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
2) 
, 
The power exerted by each student is given by
where
W is the work done
t is the time taken
For the first student, and 
, so the power exerted is
For the second student, 
and 
, so the power exerted is
