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stiv31 [10]
2 years ago
10

Urgent!Can Someone work these out, i'm kind of struggling?

Physics
1 answer:
Leya [2.2K]2 years ago
7 0

can i sent you photo in social media

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The climber dropped her compass at the end of her 240-meter climb. How long did it take to strike bottom?
ANEK [815]

240 = 0+1/2 (-9.8t

240 = -4.9t

<span>240/-4.9 = t</span><span>
</span>49.0 = t

t= 7.0s

4 0
3 years ago
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What is the power generated by a 3.7 V cell phone battery that provides 2.0 A of current?
expeople1 [14]

Answer:

7.4 watt

Explanation:

Power= V× I

= 3.7×2.0= 7.40 watt

8 0
3 years ago
Frick and Frack are standing back-to-back, leaning on each other, but not moving. If Frick weighs
mylen [45]

Answer:

Frick is pushing harder

Explanation:

if Frack weighs more and he was pushing harder they would be moving, but if Frick pushes harder then they wont move

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2 years ago
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What law describes light
Darina [25.2K]

The law of reflection

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2 years ago
A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
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