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Andru [333]
2 years ago
6

What is (5/9×(°F-32))

Mathematics
1 answer:
djyliett [7]2 years ago
6 0

Answer:

32º

Step-by-step explanation:

Fº-32 ×5/9

5/9Fº-160/9

5/9Fº =160/9

(5Fº)9=9(160)

45Fº=1440

divide both sides by 45

Fº=32

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Jeremy is going on rides at a carnival he starts the rides a 12:30 by 12:45 he had gone on 1/5 of the carnival rides at the rate
MArishka [77]

Answer:

1.25 hours or 1 hour and 15 minutes

Step-by-step explanation:

12:45 - 12:30 = :15

15 minutes equates to 1/5 of the rides

So, we multiply 15 by 5 to find the total time taken to ride all the rides.

15 x 5 = 75

75/60 = 1.25

It would take him 1.25 hours to ride all the rides at the carnival or 1 hour and 15 minutes.

8 0
3 years ago
Please please help ASAP
Dvinal [7]

Answer:

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8 0
2 years ago
In Mr. Romero's class there are 25 students, 13 participate in school sports. What percent of the class participates in school s
TEA [102]

Answer:

52 Percent participate in school sports.

Step-by-step explanation:

13/25 = x/100

Multiply 13 x 100 = 1300

Then, divide 1300 by 25 = 52

Move the decimal point two places to the left, and then you get your answer of 52%

3 0
3 years ago
Using Cramer's Rule, what is the value of x in the system of linear equations below?
Luden [163]

Answer:

0

Step-by-step explanation:

We find the determinant of a matrix by the method below. If we have a matrix:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant is ad-bc

Now, using cramer's rule, we find x-value by the formula:

x=\frac{D_x}{D}

Where D is the determinant of the original problem and D_x is the determinant of the x-value matrix. How do we get those?

<u><em>To get original matrix and thus D, we set up the matrix as the coefficients of x and y (s) of both the equations and to get matrix of x-value and thus D_x, we replace the x values of the matrix with the numbers in the right hand side of the 2 equations.</em></u> We show this below:

<em />

<em>To get D:</em>

\left[\begin{array}{cc}3&4\\1&-6\end{array}\right] \\D=(3)(-6)-(1)(4)=-18-4=-22

<em>To get D_x:</em>

<em>\left[\begin{array}{cc}12&4\\-18&-6\end{array}\right] \\D_x=(12)(-6)-(-18)(4)=0</em>

<em />

<em>Putting into the formula, we get:</em>

<em>x=\frac{D_x}{D}=\frac{0}{-22}=0</em>

<em />

<em>Thus, the value of x is 0</em>

5 0
3 years ago
I would mark brainliest!!!Does this system of equations have<br> a solution?
LiRa [457]
The answer (-3,3)
Explanation:
8 0
2 years ago
Read 2 more answers
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