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Solnce55 [7]
2 years ago
13

Well can someone help me

Chemistry
1 answer:
NNADVOKAT [17]2 years ago
5 0
Chlorophyll is an example of a pigment.
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The energy source used in nuclear power plants today is
Klio2033 [76]

Answer:

B I have taken the quiz already 90%

7 0
3 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C  

(58 g . 0.100) / 0.580 = 10 g of H

 48 g of C / 12 g/mol = 4 mol

 10 g of H / 1g/mol = 10 moles

7 0
3 years ago
Can you identify a chemical only by knowing its physical properties?
amid [387]

Answer:

Any characteristic that can be determined without changing the substance's chemical identity. chemical property: Any characteristic that can be determined only by changing a substance's molecular structure

Explanation:

4 0
2 years ago
At the equilibrium point in the decomposition of phosphorus pentachloride to chlorine and phosphorus trichloride, the following
Hitman42 [59]

Answer: K_{eq} for the reaction is 5.55

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

                        PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)          

At eqm. conc.   (0.010) M     (0.15)  M   (0.37) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.37)\times (0.15)}{(0.010)}

K_c=5.55

Thus the K_{eq} for the reaction is 5.55

5 0
3 years ago
What us a bond between a positive and a negative ion called
Nat2105 [25]

Static. Is the bond if u need 2 know

6 0
3 years ago
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