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Deffense [45]
3 years ago
15

The photo on the left shows an alligator hiding in swamp water. The photo on the right shows an alligator with a mutation for wh

ite skin. What kind of effect is the mutation most likely to have on the alligator?
A. Neutral, because it will have an easier time staying warm
B. Harmful, because it will have a harder time staying clean
C. Harmful, because it will have a harder time sneaking up on its prey
D. Beneficial, because it will have an easier time finding a mate​
Chemistry
2 answers:
Usimov [2.4K]3 years ago
4 0

Answer: C. Harmful, because it will have a harder time sneaking up on its prey

Explanation: White skin on an alligator would be detrimental because it would not be able to blend in to its surroundings as well, as the white skin would stand out from the greens and browns of the swamps in which alligators normally inhabit. Most alligators also live in warmer climates, so there would not be much opportunity to try and blend into any sort of snow.

Lilit [14]3 years ago
4 0

Answer:

c

Explanation:

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It would still have oceans but no atmospheric water in Earth if no icy debris had arrived.

A.  It would still have oceans but no atmospheric water.

<u>Explanation:</u>

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4 0
4 years ago
Brainliest and a free hug :)
nlexa [21]

Answer:

C: The atoms involved in the chemical reaction

Explanation:

In a chemical reaction, when we balance it up, the number of moles or atoms on the left side must equal that on the right hand side. And thus, the mass is found in the atoms involved in such chemical reaction.

8 0
3 years ago
During a synthesis reaction, 1.8 grams of magnesium reacted with 6.0 grams of oxygen. What is the maximum amount of magnesium ox
skelet666 [1.2K]

Answer:

2.9 grams.

Explanation:

  • From the balanced reaction:

<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.

no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.

<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.074 mol of Mg produce → 0.074 mol of MgO.

<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>

5 0
3 years ago
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