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3 years ago

The distance from a crest to a trough is called the wave length

Physics

1 answer:

V125BC [204]3 years ago

5 0

Answer:

Explanation:

The highest surface part of a wave is called the crest, and the lowest part is the trough. The vertical distance between the crest and the trough is the wave height. The horizontal distance between two adjacent crests or troughs is known as the wavelength.

I hope it's helpful!

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A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062

galina1969 [7]

Answer:

Force on the proton will be $.73\times 10^{-14}N$

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light $c=3\times 10^8m/sec$

So speed of proton $v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec$

Magnetic field B = 0.00629 T

Charge on proton $q=1.6\times 10^{-16}C$

Angle between velocity and magnetic field $\Theta =137^{\circ}$

Force on the proton is equal to $F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N$

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3 years ago

7. A car stops at a red light. The light turns green

Readme [11.4K]

Answer:

Graph C

Explanation:

This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.

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2 years ago

A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.

Natali5045456 [20]

Answer:

19.62 ms

Explanation:

t = Time taken = 2 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive)

Equation of motion

$v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/s$

The speed of the pebble when it hit the water is 19.62 ms

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3 years ago

Pls help A ball rolls horizontally off a 100-meter-tall cliff at 40 meters per second. How far does the ball travel horizontally

svet-max [94.6K]

First find the time it takes for the ball to reach the ground using the vertical component of its position vector:

$y=y_0+v_{0y}t+\dfrac12a_yt^2$

$\implies0=100\,\mathrm m+\dfrac12\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2$

$\implies t=4.52\,\mathrm s$

Meanwhile, the horizontal component of the ball's position vector is

$x=x_0+v_{0x}t+\dfrac12a_xt^2$

$\implies x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)t$

After about 4.52 s, the ball has traveled a horizontal distance of

$x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)(4.52\,\mathrm s)=180.8\,\mathrm m$

which you would round to 200 m, so the answer is B.

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3 years ago

Suppose you have a scarf that appears red when you are outside on a sunny day. Will the scarf appear red if you view it under di

Radda [10]

Answer:

actually no one weres the scarf in sunny ʕ•ε•ʔ

Explanation:

The colours we see are the wavelengths that are reflected or transmitted. For example, a red shirt looks red because the dye molecules in the fabric have absorbed the wavelengths of light from

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3 years ago