I believe the correct answer is the second option. The type of decay that characterizes the change of nuclides to their respective daughter products would be exponential decay. This type of decay is characterized by the decrease of quantity of a material according to the equation y=ab^x.
Answer:
Part A:
First, convert molarity to moles by multiplying by the volume:
0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3
d = √((x1 - x2)2 + (y1 - y2)2)
( -2 , 5 ) ( 12 , -1 )
↑ ↑ ↑ ↑
x1 y1 x2 y2
d = √((-2 - 12)2 + (5 - (-1))2) = √((-14)2 + 62) = √(196 + 36) = √232 = 2√58 ≈ 15.23
The compound 
will have a triple bond.
Explanation:
A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.
Alkanes, alkenes and alkynes are all hydrocarbons.
- General chemical formula of an alkane is
. In an alkane molecule, all the atoms will be bonded through single bonds.
For example, 
is propane.
- General chemical formula of an alkene is
. An alkene molecule will have atleast one double bond between two carbon atoms.
For example, 
is ethene.
- General chemical formula of an alkyne is
. An alkyne will have atleast one triple bond between two carbon atoms.
For example, is propyne.
Thus, we can conclude that out of the given options will have a triple bond.
