Question

The wording of these questions are confusing how would you set this up ?

Answer 1

Answer:

8. 171074.8 mL

9. 3475 mL.

Explanation:

8. Determination of the volume of the diluted solution.

Initial Molarity (M₁) = 14 M

Initial volume (V₁) = 523 mL

Final Molarity (M₂) = 0.0428 M

Final volume (V₂) =?

Using the dilution formula, we can obtain the volume of the diluted solution as follow:

M₁V₁ = M₂V₂

14 × 523 = 0.0428 × V₂

7322 = 0.0428 × V₂

Divide both side by 0.0428

V₂ = 7322 / 0.0428

V₂ = 171074.8 mL

Therefore, the volume of the diluted solution is 171074.8 mL

9. Determination of the volume of water added.

We'll begin by calculating the final volume of the solution. This can be obtained as follow:

Initial Molarity (M₁) = 3.2 M

Initial volume (V₁) = 973 mL

Final Molarity (M₂) = 0.7 M

Final volume (V₂) =?

M₁V₁ = M₂V₂

3.2 × 973 = 0.7 × V₂

3113.6 = 0.7 × V₂

Divide both side by 0.7

V₂ = 3113.6 / 0.7

V₂ = 4448 mL

Thus, the final volume of the solution is 4448 mL

Finally, we shall determine the volume of water added. This can be obtained as follow:

Initial volume (V₁) = 973 mL

Final volume (V₂) = 4448 mL

Volume of water added =?

Volume of water added = V₂ – V₁

Volume of water added = 4448 – 973

Volume of water added = 3475 mL