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vekshin1
3 years ago
5

H=1.01

Chemistry
1 answer:
meriva3 years ago
4 0

Answer:

Molality of solution=10.11 m

Explanation:

We are given that

Given mass of KCl(WB)=75.3 g

Given mass of water (WA)=100 g=100/1000=0.1 kg

1 kg=1000 g

Molar mass of H=1.01 g

Molar mass of K=39g

Molar mass of Cl=35.45 g

We have to find the molality of a solution.

Molar mass of KCl(MB)=39+35.45

Molar mass of KCl(MB) =74.45 g

Number of moles of solute (KCl)=\frac{given\;mass}{molar\;mass}=\frac{W_B}{M_B}

Number of moles of solute (KCl)=\frac{75.3}{74.45}

Number of moles of solute (KCl)=1.011 moles

Molality of solution

=\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}

Using the formula

Molality of solution=\frac{1.011}{0.1}

Molality of solution=10.11 m

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