Which compound will be the most soluble in water?<br><br> CH3CH2CH2CH2CH3

Which selection contains elements that are NOT all in the same group?

Volgvan

Answer:

Iron, copper , calcium

Explanation:

Iron , copper and calcium are present in three different groups.

Iron is present in group eight.

Copper is present in group eleven.

Calcium is present in group two.

Sodium , potassium and rubidium are present in same group i.e. group one. These are alkali metals.

Fluorine, chlorine and bromine are present in group seventeen. These are halogens.

Argon, Krypton and xenon are present in same group i.e, group eighteen. All are these noble gases.

4 0

3 years ago

What volume of product is produced when 20.0 Mg of liquid hydrogen reacts with

mihalych1998 [28]

Answer: The volume of product formed is 0.26 L

Explanation:

$\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}$

$\text{Moles of} H_2=\frac{0.02g}{2g/mol}=0.01moles$

$2H_2(l)+O_2(l)\rightarrow 2H_2O(g)$

As $O_2$ is the the excess reagent, $H_2$ is the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of $H_2$ give = 2 moles of $H_2O$

Thus 0.01 moles of $H_2$ will give = $\frac{2}{2}\times 0.01=0.01moles$ of $H_2O$

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 101.325 kPa = 1 atm

V = Volume of gas = ?

n = number of moles = 0.01

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $40^0C=(40+273)K=313K$

$V=\frac{nRT}{P}$

$V=\frac{0.01mol\times 0.0821L atm/K mol\times 313K}{1atm}=0.26L$

Thus the volume of product formed is 0.26 L

8 0

3 years ago

What is the element of lowest atomic number whose electronic configuration has four completely filled p sub shells

disa [49]

The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.

Evidently, the shell with energy level one has no p orbital.

Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.

However, we must know that the p-orbital comprises of 3 sub-orbitals namely;

p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.

Therefore, the total number of electrons in the p orbital is 6 electrons.

In essence, the element in question should have electron configuration;

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

The electron configuration above contains 54 electrons and has atomic number, 54.

In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.

Read more:

brainly.com/question/2183111

6 0

3 years ago

Answer fast plzzzzzzzz

viva [34]

Answer:

2nd and 3rd

Explanation:

5 0

3 years ago

Read 2 more answers

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²) where λ is the wavelength

Rh is Rydberg constant

n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a. n₁ = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b. n₁ = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/4² - 1/5²) = 2.468 x 10⁵/m

λ = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x (1 x10⁹ nm/m) = 4051 nm

c. n₁ = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/5²) = 7801 x 10⁵/m

λ = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

8 0

3 years ago

Which compound will be the most soluble in water? CH3CH2CH2CH2CH3