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2 years ago

Write a paragraph about Space Manned Exploration (100 pts)

2 answers:

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Space Manned Exploration, more commonly known as Human spaceflight, is a type of space travel that launches to space with a spacecraft, including crews or regular passengers. The very first launching program that NASA made was back in 1958 was the Project Mercury with the goal for the first human put into Earth's orbit to survive and come back safely. Other famous spaceflights include the 1969's first moon landing of <span>Neil Armstrong and Edwin "Buzz" Aldrin. Today, NASA has confirmed another attempt to make a spaceflight to the moon in 2020 or 2023. We aren't far from those dates, so let's see what they can do!

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Ray Of Light [21]2 years ago

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In the very beginning of the era of space exploration each new discovery definitely weighed a lot. The humanity has learnt many new amazing things and it is natural that we want to know more and more. However, do we have enough technology and intelligence for it?

Sian Meaney, a journalist and researcher at Cherwell College in Oxford, the UK, writes that such giants as China and Russia have recently made no claims to the scientific benefits of manned missions. Nevertheless, space exploration takes the money that could be spent on the development of “earthly” sciences, or on the exploration of the planet Earth itself.

The supporters of manned space missions argue that it is so natural for the human to explore new territories and acquire new knowledge. But don’t the secrets of our planet suffice to satisfy scientists’ interest? Can’t complex human body and soul be the main subjects of heavily invested studies? We still do not know the entire truth about our world. So, how dare we intrude on the one where our laws do not work?

You might be interested in

What is the atomic number for neon?

Anna35 [415]

Atomic Number for neon is 10

4 0

3 years ago

What is the total energy change for the following reaction:CO+H2O-CO2+H2

Alekssandra [29.7K]

Answer:

$\large \boxed{\text{-41.2 kJ/mol}}$

Explanation:

Balanced equation: CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)$

(a) Enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}$

(b) Total enthalpies of reactants and products

$\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}$

(c) Enthalpy of reaction $\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}$

4 0

2 years ago

The chemical formula for glucose (sugar) is C6H12O6. What are the individual numbers called in a chemical formula?

givi [52]

The individual numbers which are present in chemical formula is subscript.

<h3>What is chemical formula?</h3>

Chemical formula of any compound of chemistry consist more than one atoms in it and gives idea about the number of atoms present in that compound.

Given chemical formula of glucose is C₆H₁₂O₆.

In the given chemical formula of glucose, number which shows the amount of carbon, hydrogen and oxygen are known as subscripts.

Hence, individual number are subscript.

To know more about chemical formula, visit the below link:
brainly.com/question/1603500

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8 0

1 year ago

Enter the balanced NET IONIC equation for the potentially unbalanced equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq).

Zigmanuir [339]

Answer:

$Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)$

Explanation:

Hello!

In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:

$Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Cl^-(aq)\rightarrow AgCl(s)+Na^+(aq)+NO_3^-(aq)$

Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:

$Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)$

Which is the required net ionic equation.

Best regards!

4 0

2 years ago

A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab

77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

By definition, $pH = -log[H_3O^+]$ .
NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: $NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq)$ .
From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: $[NaOH] = [OH^-]$ .
Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: $[OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}$ .
We also know that $pOH = 14.00 - pH = -log[NaOH]$ . Take the antilog of both sides: $10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}$ .
Solve for the mass of NaOH: $m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V$ .

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

$m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g$

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2 years ago