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2 years ago

Please help me answer

Chemistry

1 answer:

ch4aika [34]2 years ago

5 0

Answer:

so stop using this app

Explanation:

thats the anser

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Give the formula of each coordination compound. Include square brackets around the coordination complex. Do not include the oxid

kogti [31]

Answer:

a) K2[Ni(CN)4]

b) Na3[Ru(NH3)2(CO3)2]

c) Pt(NH3)2Cl2

Explanation:

Coordination compounds are named in accordance with IUPAC nomenclature.

According to this nomenclature, negative ligands end with the suffix ''ato'' while neutral ligands have no special ending.

The ions written outside the coordination sphere are counter ions. Given the names of the coordination compounds as written in the question, their formulas are provided above.

8 0

3 years ago

How many molecules are in 1 mol of the chemical equation shown above

aivan3 [116]

There's 6.022×10^23 particles in 1 mole of anything

like there is 1000 grams in 1 kilogram of anything

7 0

3 years ago

What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11

san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}$

Δn = (2)-(2+1) = -1

Thus, Kp is:

$K_p= K_c\times (RT)^{-1}$

4 0

3 years ago

What law of motion does this picture represent

alukav5142 [94]

Answer: none

Explanation: there is no picture attached

7 0

3 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

nirvana33 [79]

Answer: The volume of water required is 398 mL

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

$0.16M=\frac{16g\times 1000}{251g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=398mL$

Hence, the volume of water required is 398 mL

7 0

3 years ago