Answer:
see explanation
Explanation:
To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.
P₄ + 5O₂ => 2P₂O₅
12/1 = 12 15/5 = 3
O₂ is the limiting reactant. P₄ will be in excess when rxn stops.
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Answer:
nuclear energy is the cleanest and safest energy source we have available and i agree with this statement for following reasons:
1. Nuclear power is generated by a controlled chain reaction involving the splitting of atoms. A modern nuclear power plant uses the intense heat created by this reaction to heat water and create steam, which turns a turbine and generates electricity. Whereas a coal-fired plant heats water by burning coal, a nuclear plant heats it by splitting atoms. This process is called nuclear fission.
2. Nuclear fission, in simple terms, occurs when an atom splits in two, releasing a massive amount of energy and several subatomic particles called neutrons. These neutrons, in turn, hit and split other atoms, beginning and sustaining the chain reaction. Reactor operators control this reaction in a variety of ways and thus regulate the amount of heat generated and energy produced.
3. The raw fuel for this process is the metal uranium, which must be enriched before it can be used for producing energy in commercial reactors. Enrichment is necessary because mined uranium ore is around 99.3 percent uranium-238, which, in today’s commercial power plants, does not readily split upon exposure to neutrons from the fission chain reaction, and thus makes poor fuel. The other 0.7 percent of mined uranium is uranium-235, which makes excellent fuel. The number refers to the atomic mass, or the total mass of protons and neutrons that make up the atomic nucleus. This difference in mass of the same element makes them two different isotopes of uranium. The enrichment process consists essentially of increasing the percentage of uranium-235 by decreasing the percentage (via removal) of uranium-238.
<h3>i hope you find your answer..</h3>
