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svlad2 [7]
3 years ago
7

PLEASE HELP ME

Physics
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

Determine whether the objects in the following problems have kinetic energy (KE) or potential energy (PE). Then, use the appropriate formula to calculate the answer.

You serve a volleyball with a mass of 2 kg. The ball leaves your hand with a speed of 30 m/s. The ball has kinetic energy. Calculate it.

A baby carriage is sitting at the top of a hill that is 20 m high. The carriage with the baby in it weighs 10 kg. The carriage has potential energy. Calculate it.

A car is traveling with a velocity of 20 m/s and has a weight (mass) of 1000 kg. The car has kinetic energy. Calculate it.

There is a bell at the top of a tower that is 20 m high. The bell weighs 100 kg. The bell has potential energy. Calculate it.

KE = (0.5)(m)(v)2

Here are the formulas:

m = mass (in kg

v = velocity (in m/s)

PE = mx g x h

m = mass (in kg

On Earth, gravity, g = 9.8 m/s2

h = height (in m)

Explanation:

yea thx for points.

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Convex lenses are thicker at the centers than the edges, they are known as the converging lenses. Rays of light that pass through the lens are brought closer together (they converge). When rays of light that are parallel pass through a convex lens they are refracted, the refracted rays converge at one point called the principal focus. 
4 0
3 years ago
Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
3 years ago
How much work would be needed to raise the payload from the surface of the moon (i.e., x = r) to the "end of the universe"?
meriva
Moon was rotation Earth or sun
it's own orbit . universe is not end
6 0
4 years ago
Read 2 more answers
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
sashaice [31]

Answer:

0.75 m³/s

Explanation:

Applying,

Q = vA.................... Equation 1

Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.

From the question,

Given: v = 2.5 m/s, A = 0.3 m²

Substitute these values into equation 1

Q = 2.5(0.3)

Q = 0.75 m³/s

Hence the flow rate of water in the pipe is 0.75 m³/s

4 0
3 years ago
Suppose two point charges, Q1 = -6.25 x 10-9 C and Q2 = -6.25 x 10-9 C, are separated by a distance d = 0.617 m.
n200080 [17]

Answer:

The answer to your question is the letter A) F =  9.23 x 10⁻⁷ N

Explanation:

Data

q₁ = -6.25 x 10⁻⁹ C

q₂ = -6.25 x 10⁻⁹ C

d = 0.617 m

k = 9 x 10⁹ Nm²/C²

F = ?

Formula

              F = k q₁q₂ /r²

-Substitution

              F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²

-Simplification

              F = 3.512 x 10⁻⁷ / 0.381

-Result

              F = 9.227 x 10⁻⁷ N  ≈ 9.23 x 10⁻⁷ N

8 0
3 years ago
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