The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude <em>w</em>), the normal force (mag. <em>n</em>), and the friction force (maximum mag. <em>f</em> ).
In the horizontal direction, we have
<em>n</em> cos(120º) + <em>f</em> cos(30º) = 0
-1/2 <em>n</em> + √3/2 <em>f</em> = 0
<em>n</em> = √3 <em>f</em>
and in the vertical,
<em>n</em> sin(120º) + <em>f</em> sin(30º) + (-<em>w</em>) = 0
<em>n</em> sin(120º) + <em>f</em> sin(30º) = (50 kg) (9.80 m/s²)
√3/2 <em>n</em> + 1/2 <em>f</em> = 490 N
Substitute <em>n</em> = √3 <em>f</em> and solve for <em>f</em> :
√3/2 (√3 <em>f </em>) + 1/2 <em>f</em> = 490 N
2 <em>f</em> = 490 N
<em>f</em> = 245 N
(pointed up the incline)
Answer:
Force, F = 500 N
Explanation:
Given that,
Power expanded, P = 1000 W
Distance moved by piano, d = 10 m
Time taken, t = 5 s
To find,
The force exerted by the person
Solution,
The rate at which the work is being done is called power delivered. Its formula is given by:
W is the work done, W = F × d
On rearranging the above formula to find F as :
F = 500 N
Therefore, the force exerted on the person is 500 N. Hence, this is the required solution.
Answer:
80%
Explanation:
Efficiency of machine = work output/work input ×100 %
From question, work output = 20J
Work input = 25J.
Therefore efficiency = 20/25 × 100 %
Efficiency = 20×4 %
Efficiency = 80%
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Answer:
A fault is commonly known as a rock fracture, where the two sides have been displaced, like when an earthquake happens the plates will slide against each other causing the fault to be the surface of where the rocks slipped.
