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Allushta [10]
3 years ago
13

The Embargo Act of 1807 and the Neutrality Acts

Chemistry
1 answer:
insens350 [35]3 years ago
6 0
The Embargo Act of 1807 and the Neutrality Acts of the 1930's were both attempts by the United States to avoid foreign conflicts. The correct option in regards to all the options given in the question is option "3". The Embargo Act of 1807 prohibited all kinds of exports from United states of America. This Act would treat any export as illegal. This Act was also intended to keep America from avoiding any conflicts with the warring nations. The Neutrality act was also intended towards remaining neutral towards all fighting nations.


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A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
Determine which elements or compounds are missing from the following reaction equation: hydrogen + ________ → water
Karo-lina-s [1.5K]

Answer:

Oxygen

Explanation:

Water's formula is H20. Which is two hydrogen and one oxygen.

4 0
3 years ago
If you have 547.3 grams of Ni2O, how many molecules would be present?
jasenka [17]

Answer: 8.830418848725065

Explanation:

8.830418848725065

5 0
2 years ago
How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?
V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a  1:3  mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have  2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

8 0
3 years ago
If a combination reaction takes place between potassium and chlorine what is the product
zepelin [54]
It would be potassium chloride or kcl
4 0
3 years ago
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