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MariettaO [177]

3 years ago

12

A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0

m/s? [Neglect air resistance]

1 answer:

sergey [27]3 years ago

3 0

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W= $\frac{1}{2}m(v^2-u^2)$

Using the formula

Work done, W $=\frac{1}{2}(0.145)((25)^2-0)$

Work done= $\frac{1}{2}(0.145)(625)$

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

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3 years ago

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Answer:L=109.16 m

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Given

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Final Temperature $=80^{\circ}C$

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