Question

A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0 m/s? [Neglect air resistance]

Answer 1

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=$\frac{1}{2}m(v^2-u^2)$

Using the formula

Work done, W$=\frac{1}{2}(0.145)((25)^2-0)$

Work done=$\frac{1}{2}(0.145)(625)$

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J