Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is

and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

Answer:
<em>a) 3.6 ft</em>
<em>b) 12.4 ft</em>
Explanation:
Distance between mirrors = 6.2 ft
difference from from the mirror you face = 1.8 ft
a) you stand 1.8 ft in front of the mirror you face.
According to plane mirror rules, the image formed is the same distance inside the mirror surface as the distance of the object (you) from the mirror surface. From this,
your distance from your first "front" image = 1.8 ft + 1.8 ft = <em>3.6 ft</em>
b) The mirror behind you is 6.2 - 1.8 = 4.4 ft behind you.
the back mirror will be reflected 3.6 + 4.4 = 8 ft into the front mirror,
the first image of your back will be 4.4 ft into the back mirror,
therefore your distance from your first "back" image = 8 + 4.4 = <em>12.4 ft</em>
Energy decreases as it moves uptrophic levels because energy is lost as metabolic heat when the organisms from one trophic level are consumed by organisms from the next level.Trophic level transfer efficiency (TLTE) measures the amount of energy that is transferred between trophic levels.
Answer:
Magnetic force obeys an inverse square law with distance
Explanation:
Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.

where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
![P=1027*9.81*6.25\\P=62967.93[Pa]](https://tex.z-dn.net/?f=P%3D1027%2A9.81%2A6.25%5C%5CP%3D62967.93%5BPa%5D)
The net force is:
![F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]](https://tex.z-dn.net/?f=F%20%3D%20P%2AA%5C%5CF%20%3D%2062967.93%2A0.00849%5C%5CF%20%3D%20534.6%5BN%5D)