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3 years ago

The net force acting on the ball below is ___ N

1 answer:

8 0

The net force applied to the object equals the mass of the object multiplied by the amount of its acceleration." The net force acting on the soccer ball is equal to the mass of the soccer ball multiplied by its change in velocity each second (its acceleration).

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A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.550 and

devlian [24]

To solve this exercise it is necessary to apply the concepts related to the Snells law.

The law defines that,

$n_1 sin\theta_1 = n_2 sin\theta_2$

$n_1 =$ Incident index

$n_2 =$ Refracted index

$\theta_1$ = Incident angle

$\theta_2 =$ Refracted angle

Our values are given by

$n_1 = 1.550$

$n_2 = 1.361$

$\theta_2 =90\° \rightarrow$ Refractory angle generated when light passes through the fiber.

Replacing we have,

$(1.55)sin \theta_1 = (1.361) sin90$

$sin \theta_1 = \frac{(1.361) sin90}{(1.55)}$

$\theta_1 =sin^{-1} \frac{(1.361) sin90}{(1.55)}$

$\theta_1 =61.4\°$

Now for the calculation of the maximum angle we will subtract the minimum value previously found at the angle of 90 degrees which is the maximum. Then,

$\theta_{max} = 90-\theta \\\theta_{max} =90-61.4\\\theta_{max}=28.6\°$

Therefore the critical angle for the light ray to remain insider the fiber is 28.6°

6 0

3 years ago

When it is burned, 1 gallon of gasoline produces 1.3Ã108j of energy. 1500 kg car accelerates from rest to 37 m/s in 10 s. the en

andreev551 [17]

Im sorry I dont knoow this

3 0

3 years ago

Quien me ayuda en una tarea de matemáticas de una figura geométrica que no se cómo se llama

Ilia_Sergeevich [38]

Answer:

i dont know what you mean

Explanation:

3 0

3 years ago

Read 2 more answers

A wheel, starting from rest, rotates with a constant angular acceleration of 2.80 rad/s2. During a certain 5.00 s interval, it t

igomit [66]

Answer:

a) time t1 = 2.14s

b) initial angular speed w1 = 6 rad/s

Explanation:

Given that;

Initial Angular velocity = w1

Angular distance = s = 65 rad

time = t = 5 s

Angular acceleration a = 2.80 rad/s^2

Using the equation of motion;

s = w1t + (at^2)/2

w1 = (s-0.5(at^2))/t

Substituting the values;

w1 = (65 - (0.5×2.8×5^2))/5

w1 = 6rad/s

Time to reach w1 from rest;

w1 = at1

t1 = w1/a = 6/2.8 = 2.14s

a) time t1 = 2.14s

b) initial angular speed w1 = 6 rad/s

8 0

3 years ago

Read 2 more answers

the momentum of a spring coil when the external compressing force is removed b the difference between the final momentum and the

Fed [463]

Answer:

the correct one is b

the difference between the final moment and the initial moment

Explanation:

The momentum is related to the moment

I = ΔP

∫ F dt = p_f - p₀

where p_f and p₀ are the final and initial moments, respectively

When checking the different answers, the correct one is b

the difference between the final moment and the initial moment

7 0

3 years ago