Answer:
4.5 W
Explanation:
Applying,
P = V²/(R₁+R₂).................. Equation 1
Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.
From the question,
Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00 Ω
Substitute these values into equation 1
P = 9²/(7+11)
P = 81/(18)
P = 4.5 Watt.
Hence the power dessipated by the two resistors is 4.5 watt
Answer:
R = 4.77 ohms
Explanation:
Four resistors are given such that,
R₁ = 2 ohms
R₂ = 3 ohms
R₃ = 5 ohms
R₄ = 10 ohms
Here, R₁ and R₂ in series. The equivalent is given by :
R₁₂ = R₁ + R₂
= 2 + 5
R₁₂ = 7 ohms
Similarly, R₃ and R₄ are in series. so,
R₃₄ = R₃ + R₄
= 10+5
R₃₄ = 15 ohms
Now, R₁₂ and R₃₄ are in parallel. So,
So, the equivalent resistance s 4.77 ohms.
Answer:
2 times bigger
Explanation:
hope this helps if so, please vote and mark as Brainlist! thanks and good luck!