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ddd [48]
3 years ago
9

The net force acting on the ball below is ___ N

Physics
1 answer:
yKpoI14uk [10]3 years ago
8 0

The net force applied to the object equals the mass of the object multiplied by the amount of its acceleration." The net force acting on the soccer ball is equal to the mass of the soccer ball multiplied by its change in velocity each second (its acceleration).

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Which of these is NOT an event that helped make the Moon as it is today?
-Dominant- [34]
The correct answer to the question that is stated above is letter b, <span>Plate tectonics caused lava to flow. All of the options are mentioned in the theories of the formation of the moon except for letter B.

There are 5 serious  theories about the formation of the moon,these are:
</span>The Fission Theory--
The Capture Theory--
The Condensation Theory--
The Colliding Planetesimals Theory--
<span>The Ejected Ring Theory--

See attached file for the description of each theory.</span>
4 0
3 years ago
In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

8 0
3 years ago
A coaxial cable consists of an inner conductor with radius ri = 0.20 cm and an outer radius of ro = 0.4 cm and has a length of 1
N76 [4]

Answer:

R = 1.69*10^{11} ohm

Explanation:

ri = 0.20cm

ro = 0.4 cm

length L = 13m

resistivity \rho = 2.00*10^13 ohm m

resistance can be determine by using following relation

R = \frac{\rho}{2\pi L} ln\frac{ro}{ri}

R = \frac{2.00*10^{13}}{2\pi *10} ln\frac{.004}{.002}

R = 1.69*10^{11} ohm

4 0
3 years ago
The body is subjected to a force of 0,4 N m with a shoulder of 5 cm. What is the magnitude of this force?​
igor_vitrenko [27]

Answer:

8N

Explanation:

the body is subjected to pressure equals to force force inverse to the area of that body given that it is in motion

5 0
2 years ago
A force is described by its BLANK and by the direction in which it acts
Andre45 [30]
Strength/magnitude would both work
3 0
3 years ago
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