Answer:
¿Es una pregunta de la escuela o de la vida?
Explanation:
<h2>
Answer:</h2>
105146 Pa
<h2>
Explanation:</h2>
1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.
- Pressure exerted by the compressed spring (Pspring)
- Pressure due to weight of the piston (Pw)
- Atmospheric pressure (Patm)
- Initial pressure inside the cylinder. (P1)
2) We will formulate an equation balancing all upward and downward pressures.
P1= Patm + Pw + Pspring
3) We will calculate each of the pressures separately.
P = F/A
F= ks
k= 38×1000 =38000 N m
s= 2.5 /1000 = (2.5x10^-3) m
F = 38000×(2.5x10^-3) = 95 N
A = 30/10000 = (30x10^-4) m2
P = 95 / (30x10^-4)
Pspring ≅ 3167 Pa
P = F/A
F = W = mg
W = 2×9.81 = 19.62 N
A = 30/10000 = (30x10^-4) m2
P = 19.62 / (30x10^-4)
Pw = 654 Pa
P = 1atm = 101325 Pa
Patm = 101325 Pa
4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).
P1= Patm + Pw + Pspring
P1= 101325+654+3167
P1= 105146 Pa
Answer:
Time, t = 0.25 seconds
Explanation:
Given that,
Force applied by a baseball player, F = 200 N
We need to find the time that baseball player exerts on the baseball if an impulse of 50 Ns is exerted on the baseball. The impulse exerted on the baseball is given by :
t is time taken
So, the time for which the baseball player exerts on the baseball is 0.25 seconds.
Answer:
85 K
Explanation:
T₀ = initial temperature of the gas = 77 K
T = final temperature of the gas = ?
n = number of moles of monoatomic gas = 1.00 mol
R = universal gas constant = 8.314
c = heat capacity at constant volume = (1.5) R = (1.5) (8.314) = 12.5
Q = Amount of heat absorbed = 100 J
Amount of heat absorbed is given as
Q = n c (T - T₀)
100 = (1) (12.5) (T - 77)
T = 85 K