Concentration :
196 g/L and 4 N
<h3> </h3><h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
500 cc of 2M H₂SO₄
V = 500 cc = 0.5 L
mol H₂SO₄
mass H₂SO₄ (MW = 98 g/mol)
concentration in g/L :
concentration in normality
Relationship between normality and molarity
N = M x n (n=valence , amount of H⁺ or OH⁻)
so :
Solution:
The calculation is:
6.28 * 10^13 + 9.30 * 10^11
6.28 * 10^2 * 10^11 + 9.30 * 10^11
(628 + 9.30) * 10^11
637.3 * 10^11
Answer:
22)convex
23)sun (sunlight reflect of the off the surface of the moon
24)because of the way the atmosphere interacts with sunlight
25) transparent : glass,contact lenses,water,air
translucent: wax paper, oil paper, thin sheets
opaque : plastic, wood, leather
26)when light react with opaque: none of it passes though
when it reacts with transparent : it passes through
when it react with translucent : only some of it passes through, the light does not pass directly through the material
Explanation:
24 blue light is scattered in all directions by the tiny molecules of air in earth's atmosphere
Answer:
k is 3,18*10⁻² s⁻¹ at 75°C
Explanation:
following Arrhenius equation:
k= k₀*e^(-Ea/RT)
where k= rate constant , k₀= frequency factor , Ea= activation energy , R= universal gas constant T=absolute temperature
then for T₁=25°C =298 K
k₁= k₀*e^(-Ea/RT₁)
and for T₁=75°C = 348 K
k₂= k₀*e^(-Ea/RT₂)
dividing both equations
k₂/k₁= e^(-Ea/RT₂+Ea/RT₁ )
k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )]
replacing values
k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )] = 4,7*10⁻³ s⁻¹ *e^[-33.6*1000 J/mol /8.314 J/molK*(1/ 348 K -1/298 K )] = 3,18*10⁻² s⁻¹
thus k is 3,18*10⁻² s⁻¹ at 75°C
Answer:
1.44mole of CO
Explanation:
The reaction equation is given as:
5C + 2SO₂ → CS₂ + 4CO
We check to see if the expression is balanced and it is so;
Now;
Given;
1.8mole of C reacted; how many moles of CO are produced;
From the balanced reaction equation:
5 mole of C is expected to produce 4 mole of CO
1.8 mole of C will then produce 
= 1.44mole of CO
