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zhuklara [117]
3 years ago
5

The air is partially removed at the upper part of the tube and the valve is closed. The height of the water above its pool surfa

ce is 0.7 m.The height of the liquid above its pool surface is 0.33 m.The difference in the heights of the pool surfaces is 0.22 m.
Required:
Find the density of the unknown liquid.

Physics
1 answer:
torisob [31]3 years ago
7 0

Answer:

2121.2kg/m^3 is the density of the test liquid on the left

Explanation:

See attached file

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Answer:

t = 3 seconds

Explanation:

Given that,

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Let a be the acceleration and t is time.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(30)^2-u^2}{2(45)}\\\\=10\ m/s^2

Now finding time.

t=\dfrac{v-u}{a}\\\\t=\dfrac{30-0}{10}\\\\t=3\ s

So, the required time is 3 seconds.

8 0
3 years ago
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Anastasy [175]
Frequency = 1/T
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